Verilog设计要求: 1、东西、南北各有红、黄、绿指示灯 2、绿灯、黄灯和红灯的持续时间分别为40s、5s和45s
时间: 2023-07-10 11:35:45 浏览: 151
好的,以下是一个简单的Verilog代码来实现一个包含东西、南北各有红、黄、绿指示灯的交通灯系统,并且绿灯、黄灯和红灯的持续时间分别为40秒、5秒和45秒:
```
module traffic_light(
input clk,
output reg EW_red,
output reg EW_yellow,
output reg EW_green,
output reg NS_red,
output reg NS_yellow,
output reg NS_green
);
reg [3:0] state;
reg [5:0] counter;
localparam S_EW_GREEN = 4'b0001;
localparam S_EW_YELLOW = 4'b0010;
localparam S_NS_RED = 4'b0011;
localparam S_NS_GREEN = 4'b0100;
localparam S_NS_YELLOW = 4'b0101;
localparam S_EW_RED = 4'b0110;
always @(posedge clk) begin
counter <= counter + 1;
case(state)
S_EW_GREEN: begin
EW_red <= 0;
EW_yellow <= 0;
EW_green <= 1;
NS_red <= 1;
NS_yellow <= 0;
NS_green <= 0;
if(counter == 40000000) begin
state <= S_EW_YELLOW;
counter <= 0;
end
end
S_EW_YELLOW: begin
EW_red <= 0;
EW_yellow <= 1;
EW_green <= 0;
NS_red <= 1;
NS_yellow <= 0;
NS_green <= 0;
if(counter == 5000000) begin
state <= S_NS_RED;
counter <= 0;
end
end
S_NS_RED: begin
EW_red <= 1;
EW_yellow <= 0;
EW_green <= 0;
NS_red <= 0;
NS_yellow <= 0;
NS_green <= 1;
if(counter == 45000000) begin
state <= S_NS_GREEN;
counter <= 0;
end
end
S_NS_GREEN: begin
EW_red <= 1;
EW_yellow <= 0;
EW_green <= 0;
NS_red <= 0;
NS_yellow <= 0;
NS_green <= 1;
if(counter == 40000000) begin
state <= S_NS_YELLOW;
counter <= 0;
end
end
S_NS_YELLOW: begin
EW_red <= 1;
EW_yellow <= 0;
EW_green <= 0;
NS_red <= 0;
NS_yellow <= 1;
NS_green <= 0;
if(counter == 5000000) begin
state <= S_EW_RED;
counter <= 0;
end
end
S_EW_RED: begin
EW_red <= 1;
EW_yellow <= 0;
EW_green <= 0;
NS_red <= 0;
NS_yellow <= 0;
NS_green <= 1;
if(counter == 45000000) begin
state <= S_EW_GREEN;
counter <= 0;
end
end
endcase
end
endmodule
```
这个代码使用一个有限状态机来控制交通灯的状态,包括东西和南北方向的红、黄、绿灯。在每个时钟周期的上升沿,状态机会根据当前的状态来决定下一个状态,并相应地控制交通灯的输出。同时,还使用了一个计数器来计算绿灯、黄灯和红灯的持续时间,并在达到预设时间后切换到下一个状态。
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