JAVA编写一个测试类，要求： 创建5个点，即5个Point对象 输出X坐标最大的点的坐标。 输出点关于原点的对称点。 分别输出两点间距离最近和最远的距离。

好的，以下是我给出的答案：

public class TestPoint {
    public static void main(String[] args) {
        Point[] points = new Point[5];
        points[0] = new Point(1, 2);
        points[1] = new Point(3, 4);
        points[2] = new Point(5, 6);
        points[3] = new Point(7, 8);
        points[4] = new Point(9, 10);

        // 输出X坐标最大的点的坐标
        Point maxX = points[0];
        for (int i = 1; i < points.length; i++) {
            if (points[i].getX() > maxX.getX()) {
                maxX = points[i];
            }
        }
        System.out.println("X坐标最大的点的坐标为：" + maxX.toString());

        // 输出点关于原点的对称点
        for (int i = 0; i < points.length; i++) {
            Point symmetrical = new Point(-points[i].getX(), -points[i].getY());
            System.out.println(points[i].toString() + "关于原点的对称点为：" + symmetrical.toString());
        }

        // 分别输出两点间距离最近和最远的距离
        double minDistance = Double.MAX_VALUE;
        double maxDistance = Double.MIN_VALUE;
        for (int i = 0; i < points.length; i++) {
            for (int j = i + 1; j < points.length; j++) {
                double distance = points[i].distance(points[j]);
                if (distance < minDistance) {
                    minDistance = distance;
                }
                if (distance > maxDistance) {
                    maxDistance = distance;
                }
            }
        }
        System.out.println("两点间距离最近的距离为：" + minDistance);
        System.out.println("两点间距离最远的距离为：" + maxDistance);
    }
}

希望我的回答能够帮到你！