float a;float b; float func(int n) { if (n == θ) { return a; } if (n == 1) { return b; return (1+func(n-1))/func(n-2) }请将递归形式的函数func,改写成非递归的形式
时间: 2023-06-13 14:08:15 浏览: 37
下面是将递归函数 `func` 改写为非递归形式的代码:
```
float a;
float b;
float func(int n) {
if (n == θ) {
return a;
}
if (n == 1) {
return b;
}
float f0 = a;
float f1 = b;
float f2 = 0;
for (int i = 2; i <= n; i++) {
f2 = (1 + f1) / f0;
f0 = f1;
f1 = f2;
}
return f2;
}
```
该代码中,使用循环代替递归,通过计算 `f0`、`f1`、`f2` 三个变量的值,依次推导出 `func(n)` 的结果,最终返回 `f2`。
相关问题
golang正则匹配b=开头\n结尾
在 Golang 中,可以使用 `regexp` 包来进行正则表达式匹配。以下是匹配以 `b=` 开头,以 `\n` 结尾的正则表达式示例代码:
```go
package main
import (
"fmt"
"regexp"
)
func main() {
re := regexp.MustCompile(`^b=.*\n$`)
str := "b=hello world\n"
if re.MatchString(str) {
fmt.Println("Matched!")
} else {
fmt.Println("Not matched!")
}
}
```
在上面的代码中,我们使用 `regexp.MustCompile()` 函数创建了一个正则表达式对象,然后使用 `MatchString()` 方法对指定的字符串进行匹配。如果匹配成功,输出 `Matched!`;否则输出 `Not matched!`。
n = 2 def func(a, b):n=return a*bs = func("ok", 3)print(s, n)
There are a couple of errors in this code:
1. The line `n=` is incomplete and does not contain a valid value assignment.
2. The `return` statement is missing a value to return.
Here's the corrected code:
```python
n = 2
def func(a, b):
return a * b
s = func("ok", 3)
print(s, n)
```
Output:
```
okok 2
```
Explanation:
- The variable `n` is assigned the value `2`.
- The function `func()` takes two arguments `a` and `b`, and returns their product.
- The function is called with `"ok"` and `3` as arguments, and their product `"okok"` is assigned to the variable `s`.
- The values of `s` and `n` are printed. `s` is `"okok"` and `n` is `2`.
Note that the `n` variable inside the function is not the same as the `n` variable outside the function. They have different scopes, and modifying one does not affect the other.