思路: 首先需要设定游戏的条件和提示,并生成需要猜测的单词或组合。 玩家或电脑每次猜测时,需要输入一个字母或组合,并判断其是否出现在正确答案中。 如果猜测正确,则显示正确的字母或组合,并更新当前猜出的残缺单词或猜测的组合情况。 如果猜测错误,则显示已经猜错的字母,并减少剩余猜错次数。 当剩余猜错次数为0时,游戏结束,显示正确答案并询问是否重新开始游戏。 如果猜测正确,则游戏胜利,显示胜利信息,并询问是否重新开始游戏。 添加是否在玩一次功能,根据玩家的选择决定是否重新开始游戏。c++
时间: 2023-12-10 12:41:16 浏览: 103
以下是一份示范代码,实现了一个简单的猜单词游戏:
```c++
#include <iostream>
#include <string>
#include <vector>
#include <ctime>
#include <cstdlib>
using namespace std;
const int MAX_WRONG = 8; // 最大允许猜错次数
vector<string> words; // 需要猜测的单词或组合
void init_words() {
words.push_back("GUESS");
words.push_back("HANGMAN");
words.push_back("DIFFICULT");
words.push_back("COWBOY");
words.push_back("JAVASCRIPT");
}
int main() {
srand(static_cast<unsigned int>(time(0)));
init_words();
char play_again = 'y';
do {
const string THE_WORD = words[rand() % words.size()]; // 随机选取一个单词或组合
int wrong = 0; // 已经猜错的次数
string so_far(THE_WORD.size(), '-'); // 当前已经猜对的字母或组合情况
string used = ""; // 已经猜过的字母或组合
cout << "Welcome to Hangman. Good luck!\n";
// 开始猜测
while ((wrong < MAX_WRONG) && (so_far != THE_WORD)) {
cout << "\n\nYou have " << MAX_WRONG - wrong << " incorrect guesses left.\n";
cout << "\nYou've used the following letters:\n" << used << endl;
cout << "\nSo far, the word is:\n" << so_far << endl;
char guess;
cout << "\n\nEnter your guess: ";
cin >> guess;
guess = toupper(guess); // 转换为大写字母
while (used.find(guess) != string::npos) {
cout << "\nYou've already guessed " << guess << endl;
cout << "Enter your guess: ";
cin >> guess;
guess = toupper(guess);
}
used += guess;
if (THE_WORD.find(guess) != string::npos) {
cout << "That's right! " << guess << " is in the word.\n";
// 更新已经猜对的情况
for (int i = 0; i < THE_WORD.length(); ++i) {
if (THE_WORD[i] == guess) {
so_far[i] = guess;
}
}
}
else {
cout << "Sorry, " << guess << " isn't in the word.\n";
++wrong;
}
}
// 游戏结束
if (wrong == MAX_WRONG) {
cout << "\nYou've been hanged!";
}
else {
cout << "\nYou guessed it!";
}
cout << "\nThe word was " << THE_WORD << endl;
cout << "Do you want to play again? (y/n) ";
cin >> play_again;
} while (play_again == 'y');
return 0;
}
```
希望能对你有所帮助!
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