五子棋人机对弈算法设计与实现的源码
时间: 2023-11-27 14:50:24 浏览: 153
五子棋人机对弈算法设计与实现的源码是一个比较复杂的问题,需要考虑各种情况和策略。以下是一个简单的示例代码,供您参考:
```python
# 五子棋人机对弈算法设计与实现的源码
import numpy as np
# 定义常量
BOARD_SIZE = 15 # 棋盘大小
EMPTY = 0 # 空位置
BLACK = 1 # 黑子
WHITE = 2 # 白子
class ChessBoard:
def __init__(self):
self.board = np.zeros((BOARD_SIZE, BOARD_SIZE), dtype=int) # 初始化棋盘
def place(self, x, y, player):
if self.board[x, y] == EMPTY: # 如果该位置为空
self.board[x, y] = player # 放置棋子
return True
else:
return False
def get_winner(self):
for i in range(BOARD_SIZE):
for j in range(BOARD_SIZE):
if self.board[i, j] != EMPTY:
# 判断横向是否连成五子
if j <= BOARD_SIZE - 5 and \
self.board[i, j] == self.board[i, j+1] == self.board[i, j+2] == self.board[i, j+3] == self.board[i, j+4]:
return self.board[i, j] # 返回赢家
# 判断纵向是否连成五子
if i <= BOARD_SIZE - 5 and \
self.board[i, j] == self.board[i+1, j] == self.board[i+2, j] == self.board[i+3, j] == self.board[i+4, j]:
return self.board[i, j] # 返回赢家
# 判断斜向是否连成五子
if i <= BOARD_SIZE - 5 and j <= BOARD_SIZE - 5 and \
self.board[i, j] == self.board[i+1, j+1] == self.board[i+2, j+2] == self.board[i+3, j+3] == self.board[i+4, j+4]:
return self.board[i, j] # 返回赢家
if i >= 4 and j <= BOARD_SIZE - 5 and \
self.board[i, j] == self.board[i-1, j+1] == self.board[i-2, j+2] == self.board[i-3, j+3] == self.board[i-4, j+4]:
return self.board[i, j] # 返回赢家
if EMPTY not in self.board:
return 0 # 平局
else:
return None # 没有赢家
class AIPlayer:
def __init__(self, chessboard, player):
self.chessboard = chessboard
self.player = player
def get_next_move(self):
empty_positions = np.argwhere(self.chessboard.board == EMPTY) # 获取空位置
scores = np.zeros((BOARD_SIZE, BOARD_SIZE)) # 初始化得分矩阵
for i in range(BOARD_SIZE):
for j in range(BOARD_SIZE):
if self.chessboard.board[i, j] == EMPTY:
# 计算该位置的得分
scores[i, j] = self.get_position_score(i, j)
max_score = np.max(scores) # 获取最大得分
candidates = np.argwhere(scores == max_score) # 获取得分最高的位置
index = np.random.choice(len(candidates)) # 随机选择一个位置
return candidates[index][0], candidates[index][1]
def get_position_score(self, x, y):
score = 0
directions = ((1, 0), (0, 1), (1, 1), (-1, 1)) # 四个方向
for dx, dy in directions:
score += self.get_direction_score(x, y, dx, dy)
return score
def get_direction_score(self, x, y, dx, dy):
score = 0
player_count = 0
empty_count = 0
for i in range(1, 6):
xi, yi = x + i*dx, y + i*dy
if xi < 0 or xi >= BOARD_SIZE or yi < 0 or yi >= BOARD_SIZE:
break
if self.chessboard.board[xi, yi] == self.player:
player_count += 1
elif self.chessboard.board[xi, yi] == EMPTY:
empty_count += 1
if empty_count == 1:
score += 10 # 两端都有空位
elif empty_count == 2:
score += 30 # 中间有一个空位
else:
break
if player_count == 4:
score += 10000 # 连成四子
elif player_count == 3 and empty_count == 1:
score += 1000 # 连成三子
elif player_count == 2 and empty_count == 2:
score += 100 # 连成两子
elif player_count == 1 and empty_count == 3:
score += 10 # 连成一子
return score
if __name__ == '__main__':
chessboard = ChessBoard()
ai_player = AIPlayer(chessboard, BLACK)
while True:
print(chessboard.board)
x, y = map(int, input('请输入您的下棋位置(x, y): ').split())
if chessboard.place(x, y, WHITE):
winner = chessboard.get_winner()
if winner is not None:
if winner == 0:
print('平局')
elif winner == BLACK:
print('黑方赢了')
else:
print('白方赢了')
break
x, y = ai_player.get_next_move()
print('AI下棋:', x, y)
if chessboard.place(x, y, BLACK):
winner = chessboard.get_winner()
if winner is not None:
if winner == 0:
print('平局')
elif winner == BLACK:
print('黑方赢了')
else:
print('白方赢了')
break
else:
print('该位置已经有棋子,请重新输入')
```
这个示例代码简单地实现了五子棋人机对弈的功能,但是还有很多可以优化的地方。如果您想要更深入地了解五子棋人机对弈算法的实现,可以参考一些更复杂的实现或者相关的论文。
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