CBCT图像的反投影python'
时间: 2023-11-06 09:57:29 浏览: 149
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```python
import numpy as np
import scipy.ndimage as ndi
def back_projection(sinogram, theta):
"""
Back projection algorithm for CT reconstruction.
Args:
sinogram: 2D array, sinogram data
theta: 1D array, angle values in radians
Returns:
2D array, reconstructed image
"""
# Determine the shape of the sinogram and the size of the output image
num_angles, num_detectors = sinogram.shape
output_size = num_detectors
# Create empty output image
output_image = np.zeros((output_size, output_size))
# Loop over all angles
for i in range(num_angles):
# Calculate the sinogram row for the current angle
sinogram_row = sinogram[i, :]
# Calculate the angle of the current projection
angle = theta[i]
# Create an empty image for the current projection
projection_image = np.zeros((output_size, output_size))
# Loop over all detectors
for j in range(num_detectors):
# Calculate the x and y coordinates of the current detector
x = j - num_detectors / 2
y = output_size / 2
# Calculate the x and y coordinates of the current point on the projection
x_proj = x * np.cos(angle) + y * np.sin(angle)
y_proj = -x * np.sin(angle) + y * np.cos(angle)
# Round the x and y coordinates to the nearest integer
x_proj = int(round(x_proj))
y_proj = int(round(y_proj))
# Add the value of the sinogram row to the projection image
projection_image[y_proj, x_proj] = sinogram_row[j]
# Apply a smoothing filter to the projection image
projection_image = ndi.gaussian_filter(projection_image, sigma=1)
# Add the projection image to the output image
output_image += projection_image
return output_image
```
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