多个BufferedInputStream流合并成一个压缩流返回给前端
时间: 2023-10-02 19:12:30 浏览: 88
Java用Zip压缩多个文件实例源码.zip
可以使用Java中的ZipOutputStream类来实现将多个BufferedInputStream流合并成一个压缩流返回给前端的功能。具体步骤如下:
1. 创建一个ZipOutputStream对象,用于将多个流合并成一个压缩流。
```java
ZipOutputStream zipOutputStream = new ZipOutputStream(response.getOutputStream());
```
2. 循环遍历每一个需要合并的流,将其添加到ZipOutputStream中。
```java
BufferedInputStream inputStream1 = new BufferedInputStream(new FileInputStream(file1));
ZipEntry entry1 = new ZipEntry("file1.txt");
zipOutputStream.putNextEntry(entry1);
byte[] buffer1 = new byte[1024];
int bytesRead1;
while ((bytesRead1 = inputStream1.read(buffer1)) != -1) {
zipOutputStream.write(buffer1, 0, bytesRead1);
}
inputStream1.close();
zipOutputStream.closeEntry();
BufferedInputStream inputStream2 = new BufferedInputStream(new FileInputStream(file2));
ZipEntry entry2 = new ZipEntry("file2.txt");
zipOutputStream.putNextEntry(entry2);
byte[] buffer2 = new byte[1024];
int bytesRead2;
while ((bytesRead2 = inputStream2.read(buffer2)) != -1) {
zipOutputStream.write(buffer2, 0, bytesRead2);
}
inputStream2.close();
zipOutputStream.closeEntry();
```
3. 最后关闭ZipOutputStream对象,完成流合并并将压缩流返回给前端。
```java
zipOutputStream.close();
```
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