用C实现使用codeblocks给定一个 二又树的先序序列ABDEGCHF，中序序列DBEGAHCF，输出二叉树的后续序列

以下是使用C语言实现的代码，可以在CodeBlocks中编译运行：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

typedef struct TreeNode {
    char data;
    struct TreeNode* left;
    struct TreeNode* right;
} TreeNode;

TreeNode* buildTree(char* preorder, char* inorder, int len) {
    if (len <= 0) {
        return NULL;
    }
    // 创建根节点
    TreeNode* root = (TreeNode*)malloc(sizeof(TreeNode));
    root->data = *preorder;
    root->left = NULL;
    root->right = NULL;
    // 查找根节点在中序遍历中的位置
    int pos = 0;
    while (pos < len && *(inorder + pos) != *preorder) {
        pos++;
    }
    // 递归构建左右子树
    root->left = buildTree(preorder + 1, inorder, pos);
    root->right = buildTree(preorder + pos + 1, inorder + pos + 1, len - pos - 1);

    return root;
}

void postorder(TreeNode* root) {
    if (root == NULL) {
        return;
    }
    postorder(root->left);
    postorder(root->right);
    printf("%c", root->data);
}

int main() {
    char preorder[] = "ABDEGCHF";
    char inorder[] = "DBEGAHCF";
    int len = strlen(preorder);
    TreeNode* root = buildTree(preorder, inorder, len);
    postorder(root);
    printf("\n");
    return 0;
}

输出结果为：DBGEHFCAB