在mysql中,比如SELECT * from base_datainterface where f_id = '434252437088371013'这个语句。但是有可能where后面查询的f_id 这个字段在java中没有接收到值,如果没有接收到值,按照查询所有来查询,如何写sql
时间: 2024-04-10 19:26:48 浏览: 52
如果在 Java 中没有接收到 f_id 字段的值,你可以使用 IFNULL 函数来处理。IFNULL 函数接受两个参数,如果第一个参数为 NULL,则返回第二个参数的值。
以下是一个示例的 SQL 查询语句,如果在 Java 中没有接收到 f_id 字段的值,将查询所有数据:
```sql
SELECT * FROM base_datainterface WHERE f_id = IFNULL('434252437088371013', f_id)
```
这样,如果在 Java 中没有接收到 f_id 的值,IFNULL 函数会将第一个参数设为 '434252437088371013',然后将查询条件变为 `f_id = '434252437088371013'`,从而查询所有匹配的数据。
相关问题
SELECT a.comm_id, c.Title house_keeper_name, ( SELECT build.id FROM erp_base.tb_base_masterdata_resource AS resource INNER JOIN erp_base.tb_base_masterdata_resource AS unit ON unit.id = resource.parent_id INNER JOIN erp_base.tb_base_masterdata_resource AS build ON build.id = unit.parent_id WHERE resource.id = a.resource_id ) resource_group FROM tb_charge_receipts_detail a LEFT JOIN erp_base.tb_base_masterdata_resource b ON b.id = a.resource_id LEFT JOIN erp_base.rf_dictionary c ON b.house_keeper = c.id GROUP BY a.comm_id,c.Title,resource_group 这个sql在mysql中报this is incompatible with sql_mode=only_full_group_by是为什么该怎么改
该错误是因为 MySQL 的版本更新,默认启用了 `ONLY_FULL_GROUP_BY` 模式,这种模式下,`GROUP BY` 必须包含所有非聚合字段。
在这个 SQL 语句中,`SELECT` 子句中的字段 `resource_group` 不在 `GROUP BY` 中,因此 MySQL 报错。
解决这个问题的方法有两个:
1. 关闭 `ONLY_FULL_GROUP_BY` 模式
可以通过修改 MySQL 的配置文件 `my.cnf` 或者在命令行中输入如下语句来关闭该模式:
```
SET GLOBAL sql_mode=(SELECT REPLACE(@@sql_mode,'ONLY_FULL_GROUP_BY',''));
```
这种方法会影响到整个 MySQL 实例的行为,需要谨慎使用。
2. 将 `SELECT` 子句中的所有字段都放入 `GROUP BY` 中
可以将 SQL 语句修改为:
```
SELECT a.comm_id, c.Title as house_keeper_name, (
SELECT build.id
FROM erp_base.tb_base_masterdata_resource AS resource
INNER JOIN erp_base.tb_base_masterdata_resource AS unit ON unit.id = resource.parent_id
INNER JOIN erp_base.tb_base_masterdata_resource AS build ON build.id = unit.parent_id
WHERE resource.id = a.resource_id
) as resource_group
FROM tb_charge_receipts_detail a
LEFT JOIN erp_base.tb_base_masterdata_resource b ON b.id = a.resource_id
LEFT JOIN erp_base.rf_dictionary c ON b.house_keeper = c.id
GROUP BY a.comm_id, c.Title, resource_group;
```
这种方法会使 SQL 语句更加冗长,但不会影响 MySQL 的全局设置。
SELECT a.comm_id, c.Title AS house_keeper_name, ( SELECT build.id FROM erp_base.tb_base_masterdata_resource AS resource INNER JOIN erp_base.tb_base_masterdata_resource AS unit ON unit.id = resource.parent_id INNER JOIN erp_base.tb_base_masterdata_resource AS build ON build.id = unit.parent_id WHERE resource.id = a.resource_id ) AS resource_group, b.resource_type FROM tb_charge_receipts_detail a LEFT JOIN erp_base.tb_base_masterdata_resource b ON a.resource_id = b.id LEFT JOIN erp_base.rf_dictionary c ON b.house_keeper = c.id GROUP BY a.comm_id, c.Title, resource_group, b.resource_type 在mysql中报SELECT list is not in GROUP BY clause and contains nonaggregated column 'erp_charge.a.resource_id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by 如何做sql的修改
根据错误提示,可以尝试修改sql_mode,去掉only_full_group_by,或者添加a.resource_id到GROUP BY子句中,但是这样可能会导致查询结果不准确。为了避免这种情况,可以使用聚合函数来替代a.resource_id,比如使用MAX(a.resource_id)。
修改后的SQL语句如下:
SELECT a.comm_id, c.Title AS house_keeper_name,
(SELECT build.id FROM erp_base.tb_base_masterdata_resource AS resource
INNER JOIN erp_base.tb_base_masterdata_resource AS unit ON unit.id = resource.parent_id
INNER JOIN erp_base.tb_base_masterdata_resource AS build ON build.id = unit.parent_id
WHERE resource.id = a.resource_id) AS resource_group,
b.resource_type
FROM tb_charge_receipts_detail a
LEFT JOIN erp_base.tb_base_masterdata_resource b ON a.resource_id = b.id
LEFT JOIN erp_base.rf_dictionary c ON b.house_keeper = c.id
GROUP BY a.comm_id, c.Title, resource_group, b.resource_type
阅读全文