程序运行提示TypeError: 'float' object is not iterable,def search_neighborhood(x, y): neighbors = [] total = 0 count = 0 for line in lines2: row = line.split() if row[0] == x and row[1] == y: neighbors.append(int(float(row[2]))) elif row[0] > x: break if not neighbors: return 0 for val in neighbors: total += val count += 1 return total / countdef search_neighborhood(x, y): neighbors = [] total = 0 count = 0 for line in lines2: row = line.split() if row[0] == x and row[1] == y: neighbors.append(int(float(row[2]))) elif row[0] > x: break if not neighbors: return 0 for val in neighbors: total += val count += 1 return total / count
时间: 2024-03-25 10:41:26 浏览: 102
这个错误通常表示你尝试迭代一个浮点数或其他非迭代对象。在你的代码中,`TypeError` 是由以下这一行代码引起的:
```python
for val in neighbors:
```
这表明 `neighbors` 是一个浮点数或其他非迭代对象。
在你的代码中,`neighbors` 是一个空列表,它只在符合条件时添加元素。因此,如果没有符合条件的元素,`neighbors` 将保持为空列表。你可以在函数的末尾添加一个条件来检查 `neighbors` 是否为空,如果是,则返回 0。例如:
```python
def search_neighborhood(x, y):
neighbors = []
total = 0
count = 0
for line in lines2:
row = line.split()
if row[0] == x and row[1] == y:
neighbors.append(int(float(row[2])))
elif row[0] > x:
break
if not neighbors:
return 0
for val in neighbors:
total += val
count += 1
return total / count
```
这样,如果 `neighbors` 为空列表,函数将返回 0,否则将计算平均值并返回。
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