ValueError: x and y must have same first dimension, but have shapes (1,) and (1000,)
时间: 2023-11-29 13:06:18 浏览: 239
这个错误是由于 x 和 y 的长度不一致导致的。你需要确保 x 和 y 的长度相同。你可以尝试使用 `np.arange()` 函数来生成一个与 y 相同长度的数组,或者重新定义 x 以匹配 y 的长度。以下是两种方法的示例代码:
方法一:使用 `np.arange()` 函数生成一个与 y 相同长度的数组
```
import numpy as np
import matplotlib.pyplot as plt
y = np.random.randn(1000)
x = np.arange(len(y))
plt.figure()
plt.plot(x, y)
plt.xlabel("X")
plt.ylabel("Y")
plt.title("随机波形")
plt.show()
```
方法二:重新定义 x 以匹配 y 的长度
```
import numpy as np
import matplotlib.pyplot as plt
y = np.random.randn(1000)
x = np.linspace(0, 999, 1000)
plt.figure()
plt.plot(x, y)
plt.xlabel("X")
plt.ylabel("Y")
plt.title("随机波形")
plt.show()
```
这两种方法都可以确保 x 和 y 的长度相同,从而避免了出现该错误。
相关问题
raise ValueError(f"x and y must have same first dimension, but " ValueError: x and y must have same first dimension, but have shapes (1,) and (78721,)
这个错误是由于在使用某个函数时,输入的x和y的维度不匹配而引起的。具体来说,x和y的第一个维度必须相同,但是在这个例子中,x和y的第一个维度分别是1和78721,不匹配。要解决这个问题,你需要检查你的代码,确保在使用函数时x和y的维度是匹配的。你可以使用numpy的reshape函数来调整数组的形状,以确保它们的第一个维度匹配。
ValueError: x and y must have same first dimension, but have shapes (1000,) and (1,)
This error occurs when you are trying to plot two arrays with different first dimensions. The first dimension of an array refers to its size along the first axis. In this case, the error message indicates that the first dimensions of the two arrays are not the same.
For example, if you are trying to plot a line graph using the Matplotlib library and your x-axis has 1000 values and your y-axis has only one value, this error will occur because there is no way to match up the x and y values.
To fix this error, you need to make sure that the first dimensions of both arrays are the same. This can be done by either changing the shape of the arrays or by selecting a subset of the arrays.
For example, if you have two arrays x and y, and you want to plot them using Matplotlib, you can use the following code:
```python
import matplotlib.pyplot as plt
x = [1,2,3,4,5,6,7,8,9,10]
y = [5,3,6,7,8,5,6,7,8,9]
plt.plot(x, y)
plt.show()
```
In this example, both x and y have the same first dimension (10), so there will be no error when plotting the graph.
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