const para_mix_t mix_para_net[] = { MIX_PARA_NET(NULL, false, config_version, TYPE_U32, 0, 0, NULL, NULL), MIX_PARA_EXT_NET("DEFRULE", true, default_rule,input , TYPE_U8 | TYPE_ITEM, sizeof(filter_strategy) / 4, 0, filter_strategy, NULL), MIX_PARA_EXT_NET("DEFRULE", true, default_rule,forward , TYPE_U8 | TYPE_ITEM, sizeof(filter_strategy) / 4, 0, filter_strategy, NULL), MIX_PARA_EXT_NET("DEFRULE", true, default_rule,output , TYPE_U8 | TYPE_ITEM, sizeof(filter_strategy) / 4, 0, filter_strategy, NULL), MIX_PARA_EXT_NET("RINPUT1", true, input[0],action , TYPE_U8 | TYPE_ITEM, sizeof(filter_strategy) / 4, 0, filter_strategy, NULL), MIX_PARA_EXT_NET("RINPUT1", true, input[0],protol , TYPE_U8 | TYPE_ITEM, sizeof(filter_type) / 4, 0, filter_type, NULL), MIX_PARA_STR_NET("RINPUT1", true, input[0], src_addr), MIX_PARA_EXT_NET("RINPUT1", true, input[0], src_port, TYPE_U16, 0, 65535, NULL, NULL), MIX_PARA_STR_NET("RINPUT1", true, input[0], dest_addr), MIX_PARA_EXT_NET("RINPUT1", true, input[0], dest_port, TYPE_U16, 0, 65535, NULL, NULL), MIX_PARA_EXT_NET("RINPUT2", true, input[0],action , TYPE_U8 | TYPE_ITEM, sizeof(filter_strategy) / 4, 0, filter_strategy, NULL), MIX_PARA_EXT_NET("RINPUT2", true, input[0],protol , TYPE_U8 | TYPE_ITEM, sizeof(filter_type) / 4, 0, filter_type, NULL), MIX_PARA_STR_NET("RINPUT2", true, input[0], src_addr), MIX_PARA_EXT_NET("RINPUT2", true, input[0], src_port, TYPE_U16, 0, 65535, NULL, NULL), MIX_PARA_STR_NET("RINPUT2", true, input[0], dest_addr), MIX_PARA_EXT_NET("RINPUT2", true, input[0], dest_port, TYPE_U16, 0, 65535, NULL, NULL), };能将后面两个优化为1个吗？使用类似循环的方式

可以使用循环的方式将后面两个参数优化为一个。具体实现方法如下：

int input_num = 2; // 输入的个数
char input_name[2][16] = {"RINPUT1", "RINPUT2"}; // 每个输入的名称
para_mix_t input_para[2][5] = {
    {
        MIX_PARA_EXT_NET("RINPUT1", true, input[0], action, TYPE_U8 | TYPE_ITEM, sizeof(filter_strategy) / 4, 0, filter_strategy, NULL),
        MIX_PARA_EXT_NET("RINPUT1", true, input[0], protol, TYPE_U8 | TYPE_ITEM, sizeof(filter_type) / 4, 0, filter_type, NULL),
        MIX_PARA_STR_NET("RINPUT1", true, input[0], src_addr),
        MIX_PARA_EXT_NET("RINPUT1", true, input[0], src_port, TYPE_U16, 0, 65535, NULL, NULL),
        MIX_PARA_STR_NET("RINPUT1", true, input[0], dest_addr),
        MIX_PARA_EXT_NET("RINPUT1", true, input[0], dest_port, TYPE_U16, 0, 65535, NULL, NULL)
    },
    {
        MIX_PARA_EXT_NET("RINPUT2", true, input[0], action, TYPE_U8 | TYPE_ITEM, sizeof(filter_strategy) / 4, 0, filter_strategy, NULL),
        MIX_PARA_EXT_NET("RINPUT2", true, input[0], protol, TYPE_U8 | TYPE_ITEM, sizeof(filter_type) / 4, 0, filter_type, NULL),
        MIX_PARA_STR_NET("RINPUT2", true, input[0], src_addr),
        MIX_PARA_EXT_NET("RINPUT2", true, input[0], src_port, TYPE_U16, 0, 65535, NULL, NULL),
        MIX_PARA_STR_NET("RINPUT2", true, input[0], dest_addr),
        MIX_PARA_EXT_NET("RINPUT2", true, input[0], dest_port, TYPE_U16, 0, 65535, NULL, NULL)
    }
};

para_mix_t mix_para_net[] = {
    MIX_PARA_NET(NULL, false, config_version, TYPE_U32, 0, 0, NULL, NULL),
    MIX_PARA_EXT_NET("DEFRULE", true, default_rule, input, TYPE_U8 | TYPE_ITEM, sizeof(filter_strategy) / 4, 0, filter_strategy, NULL),
    MIX_PARA_EXT_NET("DEFRULE", true, default_rule, forward, TYPE_U8 | TYPE_ITEM, sizeof(filter_strategy) / 4, 0, filter_strategy, NULL),
    MIX_PARA_EXT_NET("DEFRULE", true, default_rule, output, TYPE_U8 | TYPE_ITEM, sizeof(filter_strategy) / 4, 0, filter_strategy, NULL)
};

for (int i = 0; i < input_num; i++) {
    for (int j = 0; j < 6; j++) {
        mix_para_net[3 + i * 6 + j] = input_para[i][j];
        mix_para_net[3 + i * 6 + j].name = input_name[i];
    }
}

这样就可以用循环的方式将后面两个参数优化为一个，同时也保证了每个参数的正确性。