What is the machine code of the mnemonic code “LDR r8, [r7, #4]”
时间: 2024-02-17 16:59:51 浏览: 24
The machine code of the mnemonic code "LDR r8, [r7, #4]" depends on the specific architecture and instruction set being used. However, I can provide an example of the machine code for this instruction in ARMv7-A assembly language.
In ARMv7-A assembly language, the instruction "LDR r8, [r7, #4]" would be encoded as:
```
LDR r8, [r7, #4]
```
This instruction loads a 32-bit (4-byte) value from the memory address at `r7 + 4` into register `r8`. The machine code for this instruction would be:
```
0x68 0x47
```
This is represented as two bytes in hexadecimal notation. Note that the exact machine code for this instruction may differ depending on the specific architecture and implementation.
相关问题
What is the machine code of the mnemonic code “LDR r6, [r5, #4]”
The machine code of the mnemonic code "LDR r6, [r5, #4]" depends on the specific architecture and instruction set being used.
For example, on ARMv7 architecture, the machine code for this instruction would be:
```
0x58 0x5e 0x08 0x04
```
Where:
- `0x58` is the opcode for the LDR instruction with the addressing mode as [register + immediate offset]
- `0x5e` is the encoded value of the destination register r6
- `0x08` is the encoded value of the base register r5
- `0x04` is the 12-bit immediate offset value (4 in decimal) which is added to the base register to form the memory address for data transfer.
It's worth noting that the machine code representation of instructions can vary depending on the specific processor architecture and instruction set being used.
What is the machine code of the mnemonic code “LDR r3, [r5, #2]”
The machine code of the mnemonic code "LDR r3, [r5, #2]" depends on the specific architecture and instruction set being used. However, I can provide an example of the machine code for this instruction in ARMv8-A assembly language.
In ARMv8-A assembly language, the instruction "LDR r3, [r5, #2]" would be encoded as:
```
LDR X3, [X5, #2]
```
This instruction loads a 64-bit (8-byte) value from the memory address at `X5 + 2` into register `X3`. The machine code for this instruction would be:
```
0xB8 0x21 0x58 0xB8
```
This is represented as four bytes in hexadecimal notation. Note that the exact machine code for this instruction may differ depending on the specific architecture and implementation.