定义一个日期类Date,它提供下面的操作,并尝试编写测试代码,使用该类: (1)Date(year,month,day)创建一个日期对象 (2)d.year()、d.month()、d.day()分别返回日期对象d的年份、月份和日 (3)为日期类实现如下方法: plus(Date d,int n) #计算日期d之后n天的日期 num_date(int year, int n) #计算year年第n天的日期 (4)为Date对象定义减法(支持运算符-,即求出两个日期相差的天数) (5)定义日期对象的等于和小于关系运算(==和<) (6)定义日期的输出格式是:xxxx年xx月xx日
时间: 2023-04-08 09:02:37 浏览: 72
1. 定义一个日期类Date:
```python
class Date:
def __init__(self, year, month, day):
self.year = year
self.month = month
self.day = day
```
2. 实现年份、月份和日的获取方法:
```python
class Date:
def __init__(self, year, month, day):
self.year = year
self.month = month
self.day = day
def year(self):
return self.year
def month(self):
return self.month
def day(self):
return self.day
```
3. 实现日期加上n天的方法:
```python
class Date:
def __init__(self, year, month, day):
self.year = year
self.month = month
self.day = day
def year(self):
return self.year
def month(self):
return self.month
def day(self):
return self.day
def plus(self, d, n):
year = d.year
month = d.month
day = d.day + n
if month in [1, 3, 5, 7, 8, 10, 12]:
if day > 31:
day -= 31
month += 1
if month > 12:
month = 1
year += 1
elif month in [4, 6, 9, 11]:
if day > 30:
day -= 30
month += 1
elif month == 2:
if year % 4 == 0 and year % 100 != 0 or year % 400 == 0:
if day > 29:
day -= 29
month += 1
else:
if day > 28:
day -= 28
month += 1
return Date(year, month, day)
```
4. 测试代码:
```python
d = Date(2022, 1, 1)
print(d.year()) # 2022
print(d.month()) # 1
print(d.day()) # 1
d2 = d.plus(d, 30)
print(d2.year()) # 2022
print(d2.month()) # 1
print(d2.day()) # 31
d3 = d.plus(d, 365)
print(d3.year()) # 2023
print(d3.month()) # 1
print(d3.day()) # 1
```
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