短时傅里叶变换谱图 C语言
时间: 2023-10-04 10:14:13 浏览: 114
短时傅里叶变换及其谱图分析.docx
短时傅里叶变换(Short-Time Fourier Transform, STFT)是一种时频分析方法,它将信号分成若干个短时窗口,对每个窗口内的信号进行傅里叶变换,然后将变换结果拼接在一起形成一个二维谱图,其中横轴表示时间,纵轴表示频率,颜色表示信号的强度。
以下是一个使用C语言实现的短时傅里叶变换谱图的示例代码:
```c
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#define PI 3.14159265358979323846
// 定义复数结构体
typedef struct {
double real;
double imag;
} complex_t;
// 计算复数加法
complex_t add(complex_t a, complex_t b) {
complex_t c;
c.real = a.real + b.real;
c.imag = a.imag + b.imag;
return c;
}
// 计算复数乘法
complex_t mul(complex_t a, complex_t b) {
complex_t c;
c.real = a.real * b.real - a.imag * b.imag;
c.imag = a.real * b.imag + a.imag * b.real;
return c;
}
// 计算离散傅里叶变换
void dft(complex_t *x, int N) {
complex_t *X = (complex_t *)malloc(N * sizeof(complex_t));
for (int k = 0; k < N; k++) {
X[k].real = 0;
X[k].imag = 0;
for (int n = 0; n < N; n++) {
complex_t W;
W.real = cos(2 * PI * k * n / N);
W.imag = -sin(2 * PI * k * n / N);
X[k] = add(X[k], mul(x[n], W));
}
}
for (int k = 0; k < N; k++) {
x[k] = X[k];
}
free(X);
}
// 计算短时傅里叶变换
void stft(double *x, int N, int M, int L, complex_t **S) {
complex_t *window = (complex_t *)malloc(L * sizeof(complex_t));
for (int n = 0; n < L; n++) {
window[n].real = cos(2 * PI * n / L);
window[n].imag = -sin(2 * PI * n / L);
}
for (int m = 0; m < M; m++) {
complex_t *X = (complex_t *)malloc(L * sizeof(complex_t));
for (int n = 0; n < L; n++) {
X[n].real = x[m * L + n] * window[n].real;
X[n].imag = x[m * L + n] * window[n].imag;
}
dft(X, L);
for (int k = 0; k < L; k++) {
S[m][k] = X[k];
}
free(X);
}
free(window);
}
// 绘制二维谱图
void plot(complex_t **S, int M, int L) {
for (int k = 0; k < L / 2 + 1; k++) {
for (int m = 0; m < M; m++) {
double P = sqrt(S[m][k].real * S[m][k].real + S[m][k].imag * S[m][k].imag);
printf("%lf ", P);
}
printf("\n");
}
}
int main() {
int N = 1024; // 信号长度
int M = 32; // 窗口数量
int L = 32; // 窗口长度
double *x = (double *)malloc(N * sizeof(double));
for (int n = 0; n < N; n++) {
x[n] = sin(2 * PI * 50 * n / N) + sin(2 * PI * 100 * n / N);
}
complex_t **S = (complex_t **)malloc((L / 2 + 1) * sizeof(complex_t *));
for (int k = 0; k < L / 2 + 1; k++) {
S[k] = (complex_t *)malloc(M * sizeof(complex_t));
}
stft(x, N / L, M, L, S);
plot(S, M, L);
for (int k = 0; k < L / 2 + 1; k++) {
free(S[k]);
}
free(S);
free(x);
return 0;
}
```
该示例代码生成一个由两个正弦波叠加而成的信号,并使用短时傅里叶变换将其分成32个窗口,每个窗口长度为32。最终输出一个32行、16列的二维谱图,其中每个元素表示对应时间和频率上的信号强度。
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