用C语言实现

好的，以下是用 C 语言实现读取两个超大数相加的链表的示例代码。因为 C 语言没有现成的链表类，所以我们需要手动实现链表的相关操作。

#include <stdio.h>
#include <stdlib.h>

struct ListNode {
    int val;
    struct ListNode* next;
};

struct ListNode* createList(int* nums, int size) {
    struct ListNode* dummy = (struct ListNode*)malloc(sizeof(struct ListNode));
    dummy->next = NULL;
    struct ListNode* cur = dummy;
    for (int i = 0; i < size; i++) {
        cur->next = (struct ListNode*)malloc(sizeof(struct ListNode));
        cur->next->val = nums[i];
        cur->next->next = NULL;
        cur = cur->next;
    }
    return dummy->next;
}

struct ListNode* addTwoNumbers(struct ListNode* l1, struct ListNode* l2) {
    struct ListNode* dummy = (struct ListNode*)malloc(sizeof(struct ListNode));
    dummy->next = NULL;
    struct ListNode* cur = dummy;
    int carry = 0;
    while (l1 || l2) {
        int val1 = l1 ? l1->val : 0;
        int val2 = l2 ? l2->val : 0;
        int s = val1 + val2 + carry;
        cur->next = (struct ListNode*)malloc(sizeof(struct ListNode));
        cur->next->val = s % 10;
        cur->next->next = NULL;
        carry = s / 10;
        cur = cur->next;
        if (l1) {
            l1 = l1->next;
        }
        if (l2) {
            l2 = l2->next;
        }
    }
    if (carry) {
        cur->next = (struct ListNode*)malloc(sizeof(struct ListNode));
        cur->next->val = carry;
        cur->next->next = NULL;
    }
    return dummy->next;
}

void printList(struct ListNode* head) {
    while (head) {
        printf("%d ", head->val);
        head = head->next;
    }
    printf("\n");
}

int main() {
    int nums1[] = {9, 9, 9, 9, 9, 9, 9};
    int nums2[] = {9, 9, 9, 9};
    struct ListNode* l1 = createList(nums1, sizeof(nums1) / sizeof(int));
    struct ListNode* l2 = createList(nums2, sizeof(nums2) / sizeof(int));
    struct ListNode* result = addTwoNumbers(l1, l2);
    printList(result);
    return 0;
}

这个实现同样可以处理链表中任意长度的数，并且可以处理进位的情况。