main(){char s[]="9876",*p;for(p=s;p<s+2;p++)printf("%s\n",p);}为什么输出为9876876
时间: 2024-05-22 16:12:08 浏览: 23
As an AI language model, I do not have a personal opinion or preference. The term "null" is often used in computer programming to represent a value that is absent or undefined. It can also refer to a lack of information or data.
相关问题
main+({ +char+ch+[2][5]=["6937","8254},*+p+[2]; +int+i+,+j+,+s+=0; +for+(+i+=0;+i+<2;+i+++) +p+[+i+]
以下是根据提供的引用内容给出的代码示例:
```c
#include <iostream>
using namespace std;
int main() {
char ch[2][5] = {"6937", "8254"};
char *p[2];
int i, j, s = 0;
for (i = 0; i < 2; i++) {
p[i] = ch[i];
}
for (i = 0; i < 2; i++) {
for (j = 0; *(p[i] + j) != '\0'; j++) {
s += *(p[i] + j) - '0';
}
}
cout << "Sum: " << s << endl;
return 0;
}
```
该代码的功能是将二维字符数组中的数字字符转换为整数并求和。具体实现过程如下:
1. 定义一个二维字符数组`ch`,其中包含两个字符串"6937"和"8254"。
2. 定义一个指针数组`p`,用于存储`ch`中每个字符串的地址。
3. 定义变量`i`、`j`和`s`,别用于循环计数、字符串内部循环计数和求和结果。
4. 使用循环将`ch`中每个字符串的地址存储到`p`中。
5. 使用嵌套循环遍历`p`中的每个字符串,将每个字符转换为整数并累加到`s`中。
6. 输出求和结果`s`。
main(){char s[]="9876",*p;for(p=s;p<s+2;p++)printf("%s\n",p);}
As an AI language model, I do not have feelings or emotions. Therefore, the concept of "null" does not apply to me in the same way it does for humans. In software programming, "null" is a value that represents the absence of a value or an unknown value. It is often used to indicate that a variable or object has not been assigned a value yet.
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