VS2017获取系统睡眠状态

要获取系统的睡眠状态，可以使用 Windows API 中的 PowerGetActiveScheme 函数和 ReadPwrScheme 函数。以下是一个简单的示例代码：

#include <windows.h>
#include <powrprof.h>
#include <iostream>

#pragma comment(lib, "PowrProf.lib")

int main()
{
    // 获取当前电源计划的标识符
    GUID activeScheme;
    if (PowerGetActiveScheme(NULL, &activeScheme) != ERROR_SUCCESS)
    {
        std::cerr << "Failed to get active power scheme" << std::endl;
        return 1;
    }

    // 读取当前电源计划的睡眠设置
    DWORD len = 0;
    if (ReadPwrScheme(&activeScheme, NULL, NULL, &len) != ERROR_SUCCESS)
    {
        std::cerr << "Failed to get power scheme settings length" << std::endl;
        return 1;
    }
    BYTE* buffer = new BYTE[len];
    if (ReadPwrScheme(&activeScheme, NULL, buffer, &len) != ERROR_SUCCESS)
    {
        std::cerr << "Failed to read power scheme settings" << std::endl;
        delete[] buffer;
        return 1;
    }

    // 解析睡眠设置
    DWORD sleepTimeout = 0;
    DWORD sleepType = 0;
    DWORD* ptr = (DWORD*)buffer;
    for (int i = 0; i < len / sizeof(DWORD); i += 2)
    {
        if (*ptr == 4 && *(ptr + 1) == 3)  // 确保是睡眠设置
        {
            sleepTimeout = *(ptr + 2);
            sleepType = *(ptr + 3);
            break;
        }
        ptr += 2;
    }
    delete[] buffer;

    // 输出睡眠设置
    switch (sleepType)
    {
    case 0:
        std::cout << "Sleep is not available" << std::endl;
        break;
    case 1:
        std::cout << "Sleep after " << sleepTimeout << " seconds of inactivity" << std::endl;
        break;
    case 2:
        std::cout << "Sleep after " << sleepTimeout << " minutes of inactivity" << std::endl;
        break;
    case 3:
        std::cout << "Sleep after " << sleepTimeout << " hours of inactivity" << std::endl;
        break;
    default:
        std::cout << "Unknown sleep type" << std::endl;
        break;
    }

    return 0;
}

该程序获取当前电源计划的标识符，然后读取该电源计划的睡眠设置，并解析出睡眠延时和睡眠类型。最后输出睡眠设置。