be more detail
时间: 2024-03-15 19:45:18 浏览: 12
Certainly. The given expression is:
```
!RET & (!DFTRAMBYP & ((TENA & !QNAPA & !CENA) | (!TENA & !TONAPA & !TCENA)) IDFTRAMBYP) & EMAA[2] & EMAA[1] & EMAA[0] & EMASA
```
To apply the combination law, we can split the expression into two parts:
```
!DFTRAMBYP & ((TENA & !QNAPA & !CENA) | (!TENA & !TONAPA & !TCENA)) IDFTRAMBYP
```
and
```
!RET & EMAA[2] & EMAA[1] & EMAA[0] & EMASA
```
Then, we can apply the distributive law to the first part by expanding the expression inside the brackets:
```
!DFTRAMBYP & (TENA & !QNAPA & !CENA & IDFTRAMBYP | !TENA & !TONAPA & !TCENA & IDFTRAMBYP)
```
Finally, we can combine the two parts back into a single expression, without using brackets with `|` and `&`:
```
!RET & !DFTRAMBYP & TENA & IDFTRAMBYP & EMAA[2] & EMAA[1] & EMAA[0] & EMASA & !DFTRAMBYP & TENA & !QNAPA & !CENA & IDFTRAMBYP & !DFTRAMBYP & !TENA & !TONAPA & !TCENA & IDFTRAMBYP
```
This expression can be written in Perl code as shown earlier.
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