用python写一个排班代码,满足工作日偏好,工作时间偏好,班次时间范围2小时到4小时。员工每周最多工作40小时,每天最多工作8小时。单个班次最小2小时,最多4小时,员工可以连续排多个班次,员工最长连续工作时长:4小时。达到连续工作时长,必须安排休息时间。必须给工作时间完全覆盖午餐、晚餐时间的员工,安排午餐或晚餐时间.a. 午餐时间:时间范围(如11点到14点,一小时) b. 晚餐时间:时间范围(如17点到20点,半小时) c. 休息时间:时间范围(不限。半小时)
时间: 2023-02-24 17:15:04 浏览: 189
您好!下面是一个 Python 代码的示例,可以帮助您排班,满足您的要求。请注意,这只是一个大致的示例,可能需要根据您的实际情况进行调整和修改。
```
import itertools
import random
def schedule(employee_count, hours_per_day, lunch_start, lunch_end, dinner_start, dinner_end, rest_duration, work_preferences, time_preferences):
employee_work_hours = []
schedule = []
# Generate all possible combinations of shifts
shifts = list(itertools.combinations(range(hours_per_day), 2))
# Generate the total number of working hours for each employee
for i in range(employee_count):
employee_work_hours.append(random.randint(20, 40))
# Create the schedule for each employee
for i in range(employee_count):
current_hours = 0
current_shift = 0
employee_schedule = []
while current_hours < employee_work_hours[i]:
if current_hours + (shifts[current_shift][1] - shifts[current_shift][0]) <= employee_work_hours[i]:
current_hours += shifts[current_shift][1] - shifts[current_shift][0]
employee_schedule.append(shifts[current_shift])
current_shift += 1
else:
break
schedule.append(employee_schedule)
# Check if lunch and dinner breaks are included in the schedule
for i in range(employee_count):
for j in range(len(schedule[i])):
if schedule[i][j][0] <= lunch_start and schedule[i][j][1] > lunch_start:
schedule[i].append((lunch_start, lunch_start + rest_duration))
if schedule[i][j][0] < dinner_start and schedule[i][j][1] >= dinner_start:
schedule[i].append((dinner_start, dinner_start + rest_duration))
return schedule
# Test the schedule function with sample data
print(schedule(5, 8, 11, 14, 17, 20, 0.5, [], []))
```
这份代码使用了 itertools 库和 random 库来生成员工的工作时间和排班方案。然后通过一个循环,逐个检查员工的排班方案是否包含午餐和晚餐休息