year=int(input()) if leapyear(year): print("In %d February has 29 days."%year) else: print("In %d February has 28 days."%year)
时间: 2024-03-24 10:38:13 浏览: 25
这段代码缺少了 `leapyear()` 函数的定义,因此无法运行。可以通过下面的代码定义 `leapyear()` 函数:
```
def leapyear(year):
if year % 400 == 0:
return True
if year % 100 == 0:
return False
if year % 4 == 0:
return True
return False
```
该函数判断输入的年份 `year` 是否为闰年,如果是则返回 `True`,否则返回 `False`。可以将该函数添加到代码中,使得代码可以正常运行并输出指定年份 2 月的天数。
相关问题
问题描述】 二月通常有28天,但如果是闰年,二月就有29天。 请编写一个程序,根据用户输入的年份计算当年2月的天数并输出,其中,判断闰年请用自定义函数实现。 提示:能被400整除的是闰年,能被4整除但是不能被100整除的也是闰年 【输入形式】 整数(代表年份) 【输出形式】 In 【年份】 February has [29 or 28] days. 【样例输入】 2021 【样例输出】 In 2021 February has 28 days. 【样例说明】 【评分标准】 通过测试数据 def leapyear(x): year=int(input()) if leapyear(year): print("In %d February has 29 days."%year) else: print("In %d February has 28 days."%year)
```
def leapyear(year):
if year % 400 == 0:
return True
elif year % 4 == 0 and year % 100 != 0:
return True
else:
return False
year = int(input())
if leapyear(year):
print("In %d February has 29 days." % year)
else:
print("In %d February has 28 days." % year)
```
帮我生成这个代码的流程图:a1,b1,c1=input().split(" ") a2,b2,c2=input().split(" ") a1=int(a1) b1=int(b1) c1=int(c1) a2=int(a2) b2=int(b2) c2=int(c2) d1=[0,31,28,31,30,31,30,31,31,30,31,30,31] d2=[0,31,29,31,30,31,30,31,31,30,31,30,31] sum=0 def leapyear(x): if x%400==0 or (x%4==0 and x%100!=0): return True else: return False def cha(x,x1,x2): cum=0 if leapyear(x): for i in range(x1,x2): cum+=d2[i] else: for i in range(x1,x2): cum+=d1[i] return cum if a1==a2: if b1==b2: if c1==c2: sum+=0 else: sum+=(c2-c1) else: sum+=(cha(a1,b1,b2)+c2-c1) else: sum+=(cha(a1,b1,12)+31-c1+cha(a2,1,b2)+c2-1+1) week=sum//7+1 weekdays=sum%7+1 print(f"{week} {weekdays}")
好的,以下是代码流程图:
```
+------------------------+
| Start |
+------------------------+
|
+------------------------+
| Input a1,b1,c1 |
+------------------------+
|
+------------------------+
| Input a2,b2,c2 |
+------------------------+
|
+------------------------+
| Convert a1,b1,c1 to int |
+------------------------+
|
+------------------------+
| Convert a2,b2,c2 to int |
+------------------------+
|
+------------------------+
| Initialize d1,d2,sum |
+------------------------+
|
+------------------------+
+------------>| Define leapyear function |
| +------------------------+
| |
| +------------------------+
| | Define cha function |
| +------------------------+
| |
+-------------+---------------------------+
| If a1==a2 |
| If b1==b2 |
| If c1==c2 |
| sum+=0 |
| Else |
| sum+=(c2-c1) |
| Else |
| sum+=(cha(a1,b1,b2)+c2-c1) |
| Else |
| sum+=(cha(a1,b1,12)+31-c1+cha(a2,1,b2)+c2-1+1) |
+------------------------+
|
+------------------------+
| Calculate week |
+------------------------+
|
+------------------------+
| Calculate weekdays |
+------------------------+
|
+------------------------+
| Output week and weekdays |
+------------------------+
|
+------------------------+
| End |
+------------------------+
```
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