sum = 0 for i in range(1,11): sum += i print(sum)
时间: 2023-06-08 09:06:17 浏览: 672
这个程序的输出结果为什么是10而不是55?
答案:因为在每一次循环中,sum的值都被重置为当前的i,而不是将i加到sum中。最终的输出结果只是循环中最后一次循环的i的值。如果想让输出结果为55,则需要将sum = sum + i。
相关问题
sum = 0 for i in range(1, 11): sum += i print(sum)
This code will output the value of the variable "sum" after each iteration of the for loop.
The output will be:
1
2
3
4
5
6
7
8
9
10
This is because the variable "sum" is being assigned the value of "i" in each iteration of the loop, and then the current value of "sum" is printed. Since "i" is incrementing from 1 to 10, the output will be the numbers 1 through 10 printed on separate lines.
Note that the initial value of "sum" is 0, but it is immediately overwritten in the first iteration of the loop. If the intention was to add up the values of "i" from 1 to 10, the code should be modified as follows:
sum = 0
for i in range(1, 11):
sum += i
print(sum)
This would output the value of the variable "sum" after the loop has completed, which would be the sum of the numbers from 1 to 10 (i.e. 55).
sum=0 for i in range(100): if (%10): continue sum=sum+i print(sum)
这段代码存在语法错误,应该是:
```
sum = 0
for i in range(100):
if i % 10 == 0:
continue
sum = sum + i
print(sum)
```
这段代码的作用是计算从 1 到 99 的所有整数之和,但是跳过了所有以 0 结尾的整数。具体来说,`for` 循环遍历从 0 到 99 的所有整数,`if` 语句判断当前整数是否以 0 结尾,如果是则执行 `continue` 跳过这次循环,否则将当前整数加到 `sum` 变量中。最后输出 `sum` 变量的值。