有10个学生,每个学生的数据包括学号、姓名、3门课的成绩,从键盘输入10个学生的数据,要求打印出3门课都不及格的学生信息。c++

Sure! Here's a C++ program that allows you to input data for 10 students, including their student ID, name, and scores for 3 subjects. It then prints out the information of students who have failed in all three subjects.

#include <iostream>
using namespace std;

struct Student {
    int studentID;
    string name;
    int scores[3];
};

int main() {
    const int numStudents = 10;
    Student students[numStudents];

    // Input data for each student
    for (int i = 0; i < numStudents; i++) {
        cout << "Enter student " << i+1 << " details:" << endl;
        cout << "Student ID: ";
        cin >> students[i].studentID;
        cout << "Name: ";
        cin.ignore();
        getline(cin, students[i].name);

        for (int j = 0; j < 3; j++) {
            cout << "Enter score for subject " << j+1 << ": ";
            cin >> students[i].scores[j];
        }
    }

    // Print students with all three subjects failed
    bool found = false;
    cout << "\nStudents who failed in all three subjects:" << endl;
    for (int i = 0; i < numStudents; i++) {
        bool failed = true;
        for (int j = 0; j < 3; j++) {
            if (students[i].scores[j] >= 60) {
                failed = false;
                break;
            }
        }
        if (failed) {
            cout << "Student ID: " << students[i].studentID << endl;
            cout << "Name: " << students[i].name << endl;
            found = true;
        }
    }

    if (!found) {
        cout << "No students failed in all three subjects." << endl;
    }

    return 0;
}

You can compile and run this program to input the student data and get the desired output. Let me know if you have any further questions!