计算两数的和与差pta

以下是一个计算两数和与差的函数实现的示例代码：

void sum_diff(float op1, float op2, float *psum, float *pdiff) {
    *psum = op1 + op2;
    *pdiff = op1 - op2;
}

在这个函数中，我们使用了指针来获取计算得出的和与差。具体来说，我们将指向和与差的指针作为参数传递给函数，并在函数内部通过解引用指针来修改指针所指向的变量的值。

在主函数中，我们可以调用这个函数来计算输入的两数的和与差，并输出结果。具体代码如下：

#include <stdio.h>

void sum_diff(float op1, float op2, float *psum, float *pdiff);

int main() {
    float a, b, sum, diff;
    scanf("%f %f", &a, &b);
    sum_diff(a, b, &sum, &diff);
    printf("The sum is %.2f\nThe diff is %.2f\n", sum, diff);
    return 0;
}

相关问题

ptaC语言指针计算两数的差与和

以下是两个pta C语言指针计算两数的差与和的例子：

1.计算两数的差

#include <stdio.h>

int main()
{
    int a, b, *p1, *p2, sub;
    scanf("%d %d", &a, &b);
    p1 = &a;
    p2 = &b;
    sub = *p1 - *p2;
    printf("%d\n", sub);
    return 0;
}

2.计算两数的和

#include <stdio.h>

int main()
{
    int a, b, *p1, *p2, sum;
    scanf("%d %d", &a, &b);
    p1 = &a;
    p2 = &b;
    sum = *p1 + *p2;
    printf("%d\n", sum);
    return 0;
}

ptaC语言函数指针计算两数的差与和

以下是一个计算两数和与差的函数指针示例：

#include <stdio.h>

void sum_diff(float op1, float op2, float *psum, float *pdiff) {
    *psum = op1 + op2;
    *pdiff = op1 - op2;
}

int main() {
    float op1 = 5.0, op2 = 3.0, sum, diff;
    void (*pfunc)(float, float, float *, float *);
    pfunc = sum_diff;
    pfunc(op1, op2, &sum, &diff);
    printf("The sum of %f and %f is %f\n", op1, op2, sum);
    printf("The difference of %f and %f is %f\n", op1, op2, diff);
    return 0;
}