求一元二次方程的根pta

以下是求解一元二次方程的根的Python代码：

import math

a, b, c = map(float, input().split())

delta = b * b - 4 * a * c

if delta > 0:
    x1 = (-b + math.sqrt(delta)) / (2 * a)
    x2 = (-b - math.sqrt(delta)) / (2 * a)
    if x1.imag > x2.imag:
        x1, x2 = x2, x1
    print("{:.2f}+{:.2f}i".format(x1.real, x1.imag))
    print("{:.2f}{:.2f}i".format(x2.real, x2.imag))
elif delta == 0:
    x = -b / (2 * a)
    if x.imag >= 0:
        print("{:.2f}+{:.2f}i".format(x.real, x.imag))
    else:
        print("{:.2f}{:.2f}i".format(x.real, x.imag))
else:
    x1 = (-b + math.sqrt(-delta) * 1j) / (2 * a)
    x2 = (-b - math.sqrt(-delta) * 1j) / (2 * a)
    if x1.imag > x2.imag:
        x1, x2 = x2, x1
    print("{:.2f}+{:.2f}i".format(x1.real, x1.imag))
    print("{:.2f}{:.2f}i".format(x2.real, x2.imag))