计算正整数n1到n2的累加和(n1、n2的值由键盘输入)通过函数实现

以下是通过函数实现计算正整数n1到n2的累加和的例子：

C语言实现：

#include <stdio.h>

int add(int n1, int n2) {
    int sum = 0;
    for (int i = n1; i <= n2; i++) {
        sum += i;
    }
    return sum;
}

int main() {
    int n1, n2, s;
    printf("请输入n1的值：");
    scanf("%d", &n1);
    printf("请输入n2的值：");
    scanf("%d", &n2);
    s = add(n1, n2);
    printf("%d到%d的累加和为：%d\n", n1, n2, s);
    return 0;
}

Java实现：

import java.util.Scanner;

public class CalculateSum {
    public static int add(int n1, int n2) {
        int sum = 0;
        for (int i = n1; i <= n2; i++) {
            sum += i;
        }
        return sum;
    }

    public static void main(String[] args) {
        int n1, n2, s;
        Scanner scanner = new Scanner(System.in);
        System.out.println("请输入n1的值：");
        n1 = scanner.nextInt();
        System.out.println("请输入n2的值：");
        n2 = scanner.nextInt();
        s = add(n1, n2);
        System.out.println(n1 + "到" + n2 + "的累加和为：" + s);
    }
}