用python写一段脚本,实现用真近点角和偏心率计算出平近点角,包含迭代次数和误差率
时间: 2024-09-24 07:27:59 浏览: 31
在Python中,我们可以编写一个函数来利用真近点角(True Anomaly, \( \nu \))和偏心率(Eccentricity, \( e \))来估算平近点角(Mean Anomaly, \( M \))。由于这是一个数值计算过程,通常通过牛顿迭代法进行逼近。下面是一个简单的示例:
```python
import math
def calculate_mean_anomaly(true_anomaly, eccentricity, max_iterations=100, tolerance=1e-6):
def f(mean_anomaly):
return mean_anomaly - ecc_to_mean_anomaly(true_anomaly, eccentricity, mean_anomaly)
def df(mean_anomaly):
return 1 - ecc_derivative(mean_anomaly, true_anomaly, eccentricity)
mean_anomaly = true_anomaly
for _ in range(max_iterations):
next_mean_anomaly = mean_anomaly - f(mean_anomaly) / df(mean_anomaly)
error = abs(next_mean_anomaly - mean_anomaly)
if error < tolerance:
break
mean_anomaly = next_mean_anomaly
return next_mean_anomaly, error, max_iterations
# 辅助函数
def ecc_to_mean_anomaly(true_anomaly, ecc, mean_anomaly):
return (true_anomaly + ecc * math.sin(math.radians(true_anomaly))) % (2 * math.pi) - ecc * math.sin(math.radians(ecc * true_anomaly))
def ecc_derivative(mean_anomaly, true_anomaly, ecc):
return math.cos(math.radians(mean_anomaly)) - ecc * math.cos(math.radians(ecc * true_anomaly))
# 示例输入
true_anomaly = math.radians(90) # 真近点角(这里以90度为例)
eccentricity = 0.5 # 偏心率
mean_anomaly, error, iterations = calculate_mean_anomaly(true_anomaly, eccentricity)
print(f"平近点角: {math.degrees(mean_anomaly)}度, 迭代次数: {iterations}, 误差: {error:.6f}")
#
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