汉诺塔问题c语言循环

汉诺塔问题的C语言循环解法如下所示：

#include <stdio.h>

double NumHanoi(int index) {
    int i = 1;
    double result = 1;
    while (i < index) {
        result = 2 * result + 1;
        i++;
    }
    return result;
}

int main() {
    int n;
    scanf("%d", &n);
    printf("%.15g\n", NumHanoi(n));
    return 0;
}

这个循环解法通过分析题目情况得到汉诺塔的公式为2^n - 1，其中n为汉诺塔的总层数。循环中的变量i表示当前层数，result表示当前层数的移动步数。每次循环，result都会乘以2并加1，直到达到目标层数。最后，将结果打印出来即可。
#### 引用[.reference_title]
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