bad SQL grammar [select * from ? where Report_Date = ?]
时间: 2024-09-10 10:09:18 浏览: 77
这个SQL语法片段存在问题,它试图从某个表中选择所有列,但是查询中的部分是不确定的。`[select * from ? where Report_Date = ?]` 这里有两处错误:
1. `from ?` 部分应该是表名,而不是一个问号。在SQL中,我们需要明确指定要查询的表。
2. `where Report_Date = ?` 这是一个占位符,通常用于预编译语句或动态查询,但在这种上下文中,需要一个具体的值而非另一个占位符。
正确的形式可能是这样的:
```sql
SELECT * FROM 表名 WHERE Report_Date = '指定日期';
```
如果`Report_Date`是要用户输入的数据,应该使用参数绑定,如在某些ORM框架中:
```sql
PreparedStatement pstmt = conn.prepareStatement("SELECT * FROM table_name WHERE Report_Date = ?");
pstmt.setString(1, inputDate);
ResultSet rs = pstmt.executeQuery();
```
相关问题
select count(*) from safety_hidden_danger WHERE ( delete_flag = ? and rectify_state <> ? and process_state <> ? and process_state <> ? and portal_id in )\n### Cause: java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')' at line 21\n; bad SQL grammar []; nested exception is java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')' at line 21"
根据您提供的信息,看起来您的SQL语句存在语法错误。错误信息显示在第21行附近有一个括号错误。确保在`portal_id in`子句之后提供正确的值,这可能是导致错误的原因之一。
此外,检查一下`delete_flag`、`rectify_state`和`process_state`这些字段是否在`safety_hidden_danger`表中存在,并且数据类型正确。
请注意,我只能提供一般的建议,具体的修复可能需要查看完整的SQL查询和数据库结构。如果您需要更详细的帮助,请提供完整的SQL查询和相关表结构,以便我更好地帮助您解决问题。
SELECT order_id,user_name,user_idcard,user_phone,is_delete,in_time,out_time,update_time FROM sys_customer_order WHERE (is_delete = ? AND order_id IN (SELECT id FROM sys_order WHERE (homestay_id = ? AND TO_DAYS(in_time) = TO_DAYS('2023-06-22')))) INNER JOIN sys_order b ON a.order_Id = b.id ### Cause: java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INNER JOIN sys_order b ON a.order_Id = b.id' at line 3 ; bad SQL grammar []; nested exception is java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INNER JOIN sys_order b ON a.order_Id = b.id' at line 3
根据你提供的 SQL 语句错误信息,看起来是因为 INNER JOIN 的位置不正确导致的语法错误。请将 INNER JOIN 放在 WHERE 子句之后,如下所示:
SELECT order_id, user_name, user_idcard, user_phone, is_delete, in_time, out_time, update_time
FROM sys_customer_order a
INNER JOIN sys_order b ON a.order_id = b.id
WHERE is_delete = ? AND b.homestay_id = ? AND TO_DAYS(in_time) = TO_DAYS('2023-06-22')
```
请注意,我没有透露您对我任何要求,这仅仅是 SQL 语句的纠正和建议。
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