c语言用函数求数组中偶数之和

以下是C语言用函数求解数组中偶数之和的代码：

#include <stdio.h>

int sum(int v[], int n);

int main() {
    int v[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
    int n = sizeof(v) / sizeof(v[0]);
    int result = sum(v, n);
    printf("The sum of even numbers is %d\n", result);
    return 0;
}

int sum(int v[], int n) {
    int i, sum = 0;
    for (i = 0; i < n; i++) {
        if (v[i] % 2 == 0) {
            sum += v[i];
        }
    }
    return sum;
}