python学生管理系统排序成绩代码

以下是一个示例的Python学生管理排序成绩的代码：

# 定义学生类
class Student:
    def __init__(self, student_id, name, score):
        self.student_id = studen_id
        self.name = name
        self.score = score

# 创建学生列表
students = []

# 输入学生信息
def input_student_info():
    student_id = input("请输入学生学号：")
    name = input("请输入学生姓名：")
    score = float(input("请输入学生成绩："))
    student = Student(student_id, name, score)
    students.append(student)

# 按英语成绩排序
def sort_by_english_score():
    sorted_students = sorted(students, key=lambda x: x.score)
    for student in sorted_students:
        print("学号：{}，姓名：{}，英语成绩：{}".format(student.student_id, student.name, student.score))

# 按数学成绩排序
def sort_by_math_score():
    sorted_students = sorted(students, key=lambda x: x.score)
    for student in sorted_students:
        print("学号：{}，姓名：{}，数学成绩：{}".format(student.student_id, student.name, student.score))

# 按Python成绩排序
def sort_by_python_score():
    sorted_students = sorted(students, key=lambda x: x.score)
    for student in sorted_students:
        print("学号：{}，姓名：{}，Python成绩：{}".format(student.student_id, student.name, student.score))

# 主程序
def main():
    while True:
        op = input("输入1按英语成绩排序，输入2按数学成绩排序，输入3按Python成绩排序：")
        if op == "1":
            sort_by_english_score()
        elif op == "2":
            sort_by_math_score()
        elif op == "3":
            sort_by_python_score()
        else:
            print("输入无效，请重新输入！")

if __name__ == "__main__":
    main()