ASP.NET 4入门指南：C#与VB编程

ASP.NET,C#
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" Beginning ASP.NET 4 in C# and VB 是一本专为初学者设计的教程，由 Imar Spaanjaars 编写，并由 Microsoft Web Platform & Tools 的 Lead Program Manager Vishal R. Joshi 撰写序言。本书旨在帮助读者深入理解 ASP.NET 4 平台，使用 C# 和 Visual Basic (VB) 进行 web 应用程序开发。通过 Wrox Programmer to Programmer 系列，读者可以参与在线讨论，访问 Wrox Online Library 获取更多资源，下载 Wrox Blox 保持技术更新，并注册免费月刊获取行业动态。 在书中，作者详细介绍了以下关键知识点： 1. **ASP.NET 4 概述**：首先介绍 ASP.NET 4 的新特性和改进，包括性能优化、开发工具的更新以及更强大的网页开发支持。 2. **开始使用 ASP.NET 4**：第一章引导读者设置开发环境，创建第一个 ASP.NET Web 应用程序，理解 ASP.NET 的基本架构和生命周期。 3. **构建 ASP.NET Web 网站**：第二章涵盖如何规划和组织网站项目，使用 Visual Studio 创建网页布局，理解文件结构和配置文件。 4. **设计 Web 页面**：第三章讲解 HTML、CSS 和响应式设计，如何使用母版页（Master Pages）和布局来实现一致的页面外观，以及利用 CSS 样式表控制网页样式。 5. **使用 ASP.NET 服务器控件**：第四章深入探讨内置的服务器控件，如文本框、按钮、复选框等，以及如何使用这些控件来处理用户输入和交互。 6. **数据绑定和动态数据**：介绍如何将数据源（如数据库）与控件绑定，使用 GridView 和 ListView 控件显示和编辑数据，以及动态数据特性。 7. **状态管理**：解释视图状态（ViewState）、隐藏字段、Cookie 和 Session 等状态管理机制，以及何时选择合适的状态管理策略。 8. **页面间通信和导航**：讲解如何在页面之间传递信息，使用 QueryString、Session 和 Application 变量，以及创建自定义导航菜单。 9. **处理用户验证和错误处理**：介绍 ASP.NET 提供的验证控件，实现用户输入验证，以及如何设置和处理应用程序级别的错误。 10. **部署和发布**：涵盖将 ASP.NET 应用程序部署到 IIS 服务器的步骤，包括配置 Web 配置文件和处理权限问题。 11. **Web 服务和AJAX**：讨论如何创建和消费 Web 服务，使用 ASP.NET AJAX 扩展用户体验，实现异步操作。 12. **安全性**：介绍 ASP.NET 的身份验证和授权机制，包括 Windows 身份验证、Forms 身份验证和角色管理。 此外，本书还鼓励读者加入 Wrox 社区，通过 P2P 论坛与其他开发者交流，获取技术支持，以及利用 Wrox 提供的多种在线资源持续学习和提升 ASP.NET 开发技能。 《Beginning ASP.NET 4 in C# and VB》是 ASP.NET 4 入门者的理想指南，它不仅提供了丰富的实例和详尽的解释，还为读者提供了一个全面的学习路径，帮助他们迅速掌握 ASP.NET 开发的核心概念和技术。"

Beginning ASP.NET 4 In C# and VB

2010-07-14 上传
《 Beginning ASP.NET 4 In C# and VB 》是一本专为初学者设计的书籍，旨在引导读者深入了解ASP.NET 4框架，同时结合C#和VB两种编程语言进行讲解。这本书是《Beginning ASP.NET 3.5 In C# and VB》的更新版，更新了...

Beginning ASP.NET 4 in C# and VB代码

2013-12-01 上传
《 Beginning ASP.NET 4 in C# and VB 代码》是一个针对初学者的资源，旨在帮助读者深入理解ASP.NET 4框架，以及如何使用C#和VB.NET这两种编程语言进行开发。这本书的配套代码库提供了丰富的实例，使得理论知识能够...

Beginning ASP.NET 4 In C# and VB(C#源码)

2011-04-15 上传
Beginning ASP.NET 4 In C# and VB(C#源码)

Write a class named ProductSystem, which extends JFrame class. The appearance of the application looks like the following (as shown in Figure 1). 2. At the beginning, input name,price and number at three JTextField fields, then click “Add”button (event source), which binds to a method (event listener) that create a Product object (using name,price and number) and add it into ArrayList<Product>, at the same time display “Add Product xxx sucess!” in JTextArea on the GUI (as shown in Figure 2) 3. When click “Display” button, then read the records from ArrayList , and display the records in JTextArea on the GUI(as shown in Figure 3). 4. When click “Save to File” button, then write the records from ArrayList to file product.txt, at the same time display "file write success" in JTextArea on the GUI (as shown in Figure 4)

2023-06-07 上传
2. At the beginning, input name, price and number at three JTextField fields, then click “Add” button (event source), which binds to a method (event listener) that creates a Product object (using ...

Use the following codes as the beginning of your program. Write a program to find the largest and smallest number. The largest and smallest number needs to be saved in register r7 and r8, respectively. For ARMSim#, these numbers also need to be displayed in the console and LCD screen (use the Embest Board Plug‐In). MOV r0, #0x00002000 MOV r1, #9 STR r1, [r0],#4 MOV r1, #3 STR r1, [r0],#4 MOV r1, #1 STR r1, [r0],#4 MOV r1, #4 STR r1, [r0],#4 MOV r1, #8 STR r1, [r0],#4 MOV r1, #5 STR r1, [r0],#4 MOV r1, #7 STR r1, [r0],#4 MOV r1, #2 STR r1, [r0],#4 MOV r1, #10 STR r1, [r0],#4 MOV r1, #6 STR r1, [r0],#4

2023-05-27 上传
After executing this code, the largest number will be saved in register r7 and the smallest number will be saved in register r8. To display these numbers on the console and LCD screen, you can use the...

根据以下要求编写一个python程序1. Description Ship of Fools is a simple classic dice game. It is played with five standard 6-faced dice by two or more players. - The goal of the game is to gather a 6, a 5 and a 4 (ship, captain and crew) in the mentioned order. - The sum of the two remaining dice (cargo) is preferred as high as possible. The player with the highest cargo score wins the round. Example: - In the first round turn, if a player rolls 6 4 3 3 1 (note we five dice at the beginning), the player can bank the 6 (ship), but the rest needs to be re-rolled since there is no 5. - In the second round turn, if the player rolls 6 5 4 4 (four dice, since the 6 from last turn is banked), the player can bank the 5 (captain) and the 4 (crew). The player has three choices for the remaining 6 and 4. The player can bank both and score 10 points, or re-roll one or two of the dice and hope for a higher score. - In the second round turn, if the player instead rolled 4 4 3 1, all dice needs to be re-rolled since there is no 5.程序需要包含一下几个类.The division of responsibility between the different classes is as follows. - Die: Responsible for handling randomly generated integer values between 1 and 6. - DiceCup: Handles five objects (dice) of class Die. Has the ability to bank and release dice individually. Can also roll dice that are not banked. - ShipOfFoolsGame: Responsible for the game logic and has the ability to play a round of the game resulting in a score. Also has a property that tells what accumulated score results in a winning state, for example 21. - Player: Responsible for the score of the individual player. Has the ability, given a game logic, play a round of a game. The gained score is accumulated in the attribute score. - PlayRoom: Responsible for handling a number of players and a game. Every round the room lets each player play, and afterwards check if any player has reached the winning score.

2023-06-02 上传
elif 4 in values and not crew: dice_cup.bank(values.index(4)) crew = True cargo = sum(dice_cup.get_unbanked_values()) return cargo class Player: def __init__(self): self.score = 0 def play...

Use the following codes as the beginning of your program. Write a sort program to sort these ten numbers from largest to smallest, then save them to memory. For ARMSim#, the sorted number also need to be displayed in the console and LCD screen (use the Embest Board Plug‐In). MOV r0, #0x00002000 MOV r1, #18 STR r1, [r0],#4 MOV r1, #6 STR r1, [r0],#4 MOV r1, #2 STR r1, [r0],#4 MOV r1, #8 STR r1, [r0],#4 MOV r1, #16 STR r1, [r0],#4 MOV r1, #10 STR r1, [r0],#4 MOV r1, #14 STR r1, [r0],#4 MOV r1, #4 STR r1, [r0],#4 MOV r1, #20 STR r1, [r0],#4 MOV r1, #12 STR r1, [r0],#4

2023-05-27 上传
Sure, here's a sample program in ARM assembly language that sorts the 10 numbers in descending order using the bubble sort algorithm and saves them to memory starting from the address 0x00002000....

To rotate a letter (lowercase) means to shift it through the alphabet, wrapping around to the beginning if necessary, so ‘a’ rotated by 3 is ‘d’ and ‘a’ rotated by -1 is ‘z’. To rotate a word (all letters are lowercase), rotate each letter by the same amount. For example, “cheer” rotated by 7 is “jolly” and “melon” rotated by -10 is “cubed”. You might want to use the built-in function ord, which converts a character to a integer code, and chr, which converts integer codes to characters. Letters of the alphabet are encoded in alphabetical order, so for example: ord('c') - ord('a') == 2. Because 'c' is the two-eth letter of the alphabet. Input A string and an integer. Output A new string.

2023-05-27 上传
The `% 26` ensures that the position wraps around to the beginning if necessary, and the `+ ord('a')` converts the position back to a letter in the lowercase alphabet. Finally, the new letter is ...

## 5 请编写一代码计算以下字符串变量str1中每个单词出现的频率，并且按照频率从高到低的 # 顺序输出。 # 输出举例 ''' 'a':7 'the':7 'is': 5 'with': 4 ''' import re str1 = ''' Each rule begins with a name (which is the name defined by the rule) and ::=. A vertical bar (|) is used to separate alternatives; it is the least binding operator in this notation. A star (*) means zero or more repetitions of the preceding item; likewise, a plus (+) means one or more repetitions, and a phrase enclosed in square brackets ([ ]) means zero or one occurrences (in other words, the enclosed phrase is optional). The * and + operators bind as tightly as possible; parentheses are used for grouping. Literal strings are enclosed in quotes. White space is only meaningful to separate tokens. Rules are normally contained on a single line; rules with many alternatives may be formatted alternatively with each line after the first beginning with a vertical bar. '''

2023-05-28 上传
likewise, a plus (+) means one or more repetitions, and a phrase enclosed in square brackets ([ ]) means zero or one occurrences (in other words, the enclosed phrase is optional). The * and + ...

Write a program to 1.Setup a simulating backing store in memory. Read the data from pdata.bin to this backing store. 2.Initialize a page table for process p, set the frame number to be -1 for each page, indicating that the page is not loaded into memory yet. 3.Read logical addresses one by one from la.txt. 4.For each logical address, a)if its page has been loaded into physical memory, simply find the frame number in the page table, then generate physical address, find and print out the physical address and data inside this address. b)if the page is used for the first time, i.e., in page table, its frame number is -1，then the page that contains this address should be loaded into a free frame in physical memory (RAM). Then update the page table by adding the frame number to the right index in the page table. Then repeat 4a). Assumption: 1.Assume the file la.txt includes the sequence of generated addresses from CPU. 2.Use a part of memory as backing store that store data for a process. 3.The backing store size is 128 bytes 4.The size of process p is 128 bytes. 5.The contents of p is included in a file pdata.bin which is a binary file. 6.Use a part of memory as RAM. The size of physical memory is 256 bytes, from 0 to 255. All the physical memory is available, allocating starting from beginning in sequence. That is, allocate frame 0 first, then frame 1, then frame 2…. 7.The size of a frame is 32 bytes, i.e., 5 bits for the offset in a frame, total number of frames is 8. At beginning, no page table is available for process p.

2023-05-24 上传
4. For each logical address, the program computes the page number and offset. 5. If the page is already loaded into physical memory (i.e., its frame number is not -1), the program computes the ...
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