WinCE.net嵌入式操作系统详解：结构、开发与特点

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#include <iostream> using namespace std; struct complex //复数的结构类型 { int real; int imgn; }; //函数sub和mul的原型 /***** Begin / int sun(int c1,int c2); int mul(int c1,int c2); / End / int main() { / Begin / complex x,y,c3,c4; cin>>x.real>>x.imgn; cin>>y.real>>y.imgn; c3=sun(x,y); c4=mul(x,y); cout<<c3.real<<' '<<c3.imgn<<endl; cout<<c4.real<<' '<<c4.imgn<<endl; / End / return 0; } //函数sub和mul的定义 / Begin *****/ complex sun(complex c1,complex c2){ complex c3; c3.real=c1.real-c2.real; c3.imgn=c1.imgn-c2.imgn; return c3; } complex mul(complex c1,complex c2){ complex c3; c3.real=c1.realc2.real-c1.imgnc2.imgn; c3.imgn=c1.imgnc2.real+c1.realc2.imgn; return c3; }

复数的乘法应该是 (a + bi) * (c + di) = (ac - bd) + (ad + bc)i，而函数 mul 的实现中，ad 和 bc 的部分写反了。修改方法：将 c3.imgn=c1.imgn*c2.real+c1.real*c2.imgn; 修改为 c3.imgn=c1.real*c2.imgn+c1....

vb.net 对集合中对控件名进行排序的多种方法

在 VB.NET 中，我们可以使用以下几种方法对集合中的控件名进行排序： 1. 使用 Linq 查询： ```vb.net Dim sortedControls = Controls.Cast(Of Control)().OrderBy(Function(c) c.Name) ``` 2. 使用 List(Of T) 的...

检查 SELECT s.* FROM student s, student s2 LEFT JOIN sc c ON s.sid = c.sid LEFT JOIN sc c2 ON s2.sid = c2.sid WHERE s.sid = 1 GROUP BY s.id HAVING COUNT(c.cid) = COUNT(c2.cid);

你的查询语句有一些问题。首先，你使用了旧的隐式连接语法（FROM student s, student s2），这在现代 SQL 中不推荐使用。其次，你在 WHERE 子句中使用了错误的条件（s.sid = 1...HAVING COUNT(c.cid) = COUNT(c2.cid);

#include<iostream>class Complex {private: double real; double imag;public: Complex(double r=0.0, double i=0.0) { real = r; imag = i; } Complex operator+(Complex c2); Complex operator-(Complex c2); void display();};Complex Complex::operator+(Complex c2) { Complex c; c.real = real + c2.real; c.imag = imag + c2.imag; return c;}Complex Complex::operator-(Complex c2) { Complex c; c.real = real - c2.real; c.imag = imag - c2.imag; return c;}void Complex::display() { std::cout << "(" << real << "," << imag << ")" << std::endl;}int main() { Complex c1(4, 3), c2(2, 1), c3(0, 0); std::cout << "c1="; c1.display(); std::cout << "c2="; c2.display(); c3 = c1 - c2; std::cout << "c3="; c3.display(); c3 = c1 + c2; std::cout << "c3="; c3.display(); return 0;} 要求重载运算符函数为友元函数

}int main() { Complex c1(4, 3), c2(2, 1), c3(0, 0); std::cout ; c1.display(); std::cout << "c2="; c2.display(); c3 = c1 - c2; std::cout ; c3.display(); c3 = c1 + c2; std::cout ; c3.display(); return 0...

假设你要查询的表名为a和b,其中a有一条数据，c1=1,c2=2，其中b有两条数据，c1=1,c2=2，c3=3和c1=1,c2=2，c3=4。现有查询语句：“select a.c1,a.c2,b.c1,b.c2,b.c3 from a left join b on a.c1=b.c1”,请将这条查询语句结果优化为一条，其中结果b.c3以”[]“括住，逗号间隔

这条查询语句的结果为： ...SELECT a.c1, a.c2, b.c1, b.c2, CONCAT('[', GROUP_CONCAT(b.c3 SEPARATOR ','), ']') AS c3 FROM a LEFT JOIN b ON a.c1 = b.c1 GROUP BY a.c1, a.c2, b.c1, b.c2 ```

Select s* from student s student s2 left join sc c sc c2 on s.sid=1 and s.sid = c.sid and s2.sid =c2.sid group by s.id having count(c.cid)=count(c2.cid);

你的查询语句中存在一些错误。首先，你在选择语句中使用了错误的表别名（s* 应该是 s）。其次，你在 ON 子句中使用了错误的条件（s.sid=1），这可能导致不正确的结果。...HAVING COUNT(c.cid) = COUNT(c2.cid);

#include<iostream> using namespace std; class Complex { private: double real; double imag; public: Complex(double r=0.0,double i=0.0) { real = r; imag = i; } friend Complex operator + (Complex c1, Complex c2); friend Complex operator - (Complex c1, Complex c2); void display(); }; Complex Complex:: operator +(Complex c1, Complex c2) { Complex c; c.real = c1.real + c2.real; c.imag = c1.imag + c2.imag; return c; } Complex Complex:: operator -(Complex c1, Complex c2) { Complex c; c.real = c1.real - c2.real; c.imag = c1.imag - c2.imag; return c; } void Complex::display() { cout << "(" << real << "," << imag << ")" << endl; } int main() { Complex c1(4, 3), c2(2, 1), c3; cout << "c1="; c1.display(); cout << "c2="; c2.display(); c3 = c1 - c2; cout << "c3="; c3.display(); c3 = c1 + c2; cout << "c3="; c3.display(); return 0; } 存在的问题

在代码中，应该将 `Complex c1(4, 3), c2(2, 1), c3;` 改为 `Complex c1(4, 3), c2(2, 1), c3(0, 0);`。下面是修改后的代码： ```c++ #include class Complex { private: double real; double imag; public: ...

System.out.println(c3.c2.c);

这是一段 Java 代码，它输出了 c3 对象中 c2 对象的 c 成员变量的值。具体解释如下： - c3 是一个对象，它包含一个名为 c2 的成员变量。 - c2 也是一个对象，它包含一个名为 c 的成员变量。 - c 是一个字符串类型的...

使用jxgl数据库，查询既选修了“操作系统”又选修了“数据结构”的学生的学号和姓名。

- 通过 WHERE 子句将这些表联接起来，并且进行筛选，只保留既选修了“操作系统”又选修了“数据结构”的学生信息。 - 最后，只选择学号和姓名这两个字段，用 SELECT 子句进行选择。注意：以上 SQL 语句仅供参考，...

谈谈体系结构描述语言Aesop、MetaH、C2、Rapide、SADL、Unicon、Wright的特点

3. C2：C2是一种基于面向对象的体系结构描述语言。它支持描述对象和类之间的关系，包括继承、聚合、组合等，并提供了强大的类型系统和模块化的设计方法。 4. Rapide：Rapide是一种基于事件驱动的体系结构描述语言。...

优化这段代码 public void handForDevice(RequestEvent evt, Device device, Element element) { try { //收到的数据 JSONObject jsonObject = XmlUtils.xmlToBean(element, JSONObject.class); JSONObject request = (JSONObject) jsonObject.get("request"); C2_8Req_ReqCamResState c2_8Req_reqCamResState = JsonUtils.toBean(JsonUtils.toString(request.get("parameters")), C2_8Req_ReqCamResState.class); C2_8Res_ReqCamResState c2_8Res_ReqCamResState = new C2_8Res_ReqCamResState(); List<C2_8Res_Group> c2_8Res_groupList = new ArrayList<>(); C2_8Res_Group c2_8Res_group = new C2_8Res_Group(); List<C2_8Res_Url> c2_8Res_urlList = new ArrayList<>(); C2_8Res_Url c2_8Res_url = new C2_8Res_Url(); for (int i = 0; i < c2_8Req_reqCamResState.getGroup().getURL().size(); i++) { String resid = c2_8Req_reqCamResState.getGroup().getURL().get(i).getResId(); AjaxResult ajaxResult = remoteUserService.getCameraListById(resid); List<DeviceChannel> channerStatueList = JsonUtils.toBean(JsonUtils.toString(ajaxResult.get("data")), DeviceChannel.class); c2_8Res_url.setResId(resid); if (channerStatueList.get(i).getStatus() == 1) { c2_8Res_url.setState("有图像"); } else { c2_8Res_url.setState("无图像"); } c2_8Res_urlList.add(c2_8Res_url); } c2_8Res_group.setURL(c2_8Res_urlList); c2_8Res_groupList.add(c2_8Res_group); c2_8Res_ReqCamResState.setGroup(c2_8Res_groupList); String result = ResponseUtils.getXmlResponse(c2_8Res_ReqCamResState, method, true, null); responseQcrXmlAck(evt, result); } catch (SipException | InvalidArgumentException | ParseException e) { e.printStackTrace(); } catch (Exception e) { e.printStackTrace(); } }

最后，可以考虑使用Java 8的Stream API来简化一些操作，如循环。以下是对代码进行的一些修改和优化建议： ``` public void handleDeviceRequest(RequestEvent evt, Device device, Element element) { try { //...

你是我的python助手可以帮我写代码，https://www.bbiquge.net/modules/article/search.php?searchkey=%B6%B7%C2%DE%B4%F3%C2%BD&submit=%CB%D1%CB%F7这个网站获取源代码的文本header={'user-agent':'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/113.0.0.0 Safari/537.36 Edg/113.0.1774.57', 'referer': 'https://www.bbiquge.net/modules/article/search.php?searchkey=%B6%B7%C2%DE%B4%F3%C2%BD&submit=%CB%D1%CB%F7&__cf_chl_tk=sloS0pzp6d1uAnYpALHcgIKs4rWjKqzfIYD4OXgK2xQ-1685714391-0-gaNycGzNDBA', 'cookie':' __gads=ID=80441a18d01e55cc-226b809157da00ce:T=1677758715:RT=1685678040:S=ALNI_MboIk-dUvtHydPucNSQ4k0MMKgdqg; __gpi=UID=00000bcfc88d3faa:T=1677758715:RT=1685678040:S=ALNI_MbpuTSDhTgrw2mMv6PXbbCwD8b5AA; cf_chl_2=206d854953a2c39; cf_clearance=wLK7rF.9158UjsnSnRTVDdbk6Fc.9HIhB.p695uIhHA-1685712522-0-160; jieqiVisitTime=jieqiArticlesearchTime%3D1685713325; Hm_lvt_007bc30c1abb0ffb7a93b4f3c8e10c5e=1685343344,1685415712,1685674211,1685713326; Hm_lpvt_007bc30c1abb0ffb7a93b4f3c8e10c5e=1685713326' }请帮我写

cf_chl_2=206d854953a2c39; cf_clearance=wLK7rF.9158UjsnSnRTVDdbk6Fc.9HIhB.p695uIhHA-1685712522-0-160; jieqiVisitTime=jieqiArticlesearchTime%3D1685713325; Hm_lvt_007bc30c1abb0ffb7a93b4f3c8e10c5e=...

以下是一个flume的conf文件，请帮我逐行解释一下代码：“#定义三大组件的名称 a.sources = r a.sinks = k1 k2 k3 a.channels = c1 c2 c3 #将数据流复制给所有channel a.sources.r.selector.type = replicating # 配置Source组件 a.sources.r.type = exec a.sources.r.command = cat /home/bit/novel/novel.csv # kafka a.sinks.k1.type = org.apache.flume.sink.kafka.KafkaSink a.sinks.k1.kafka.topic = data a.sinks.k1.kafka.bootstrap.servers = localhost:9092 a.sinks.k1.kafka.flumeBatchSize = 20 a.sinks.k1.kafka.producer.acks = 1 a.sinks.k1.kafka.producer.linger.ms = 1 a.sinks.k1.kafka.producer.compression.type = snappy a.channels.c1.type = memory a.channels.c1.capacity = 100000 a.channels.c1.transactionCapacity = 100 # mysql a.sinks.k2.type =com.us.flume.MysqlSink a.sinks.k2.hostname=localhost a.sinks.k2.port=3306 a.sinks.k2.databaseName=novel a.sinks.k2.tableName=table1 a.sinks.k2.user=bit a.sinks.k2.password=123456 a.channels.c2.type = memory a.channels.c2.capacity = 100000 a.channels.c2.transactionCapactiy = 2000 # hdfs a.sinks.k3.type = hdfs a.sinks.k3.hdfs.path = hdfs://localhost:9000/user/bit/novel #积攒多少个Event才flush到HDFS一次 a.sinks.k3.hdfs.batchSize = 100 #设置文件类型，可支持压缩 a.sinks.k3.hdfs.fileType = DataStream #多久生成一个新的文件 a.sinks.k3.hdfs.rollInterval = 5 a.channels.c3.type = memory a.channels.c3.capacity =100000 a.channels.c3.transactionCapacity = 100 # Bind the source and sink to the channel a.sources.r.channels = c1 c2 c3 a.sinks.k1.channel = c1 a.sinks.k2.channel = c2 a.sinks.k3.channel = c3”

a.channels = c1 c2 c3 ``` 这三行代码定义了三个组件的名称，分别是源（source）、汇（sink）和通道（channel），这些名称将在接下来的配置中被用到。 ``` #将数据流复制给所有channel a.sources.r.selector.type ...

#定义三大组件的名称 a.sources = r a.sinks = k1 k2 k3 a.channels = c1 c2 c3 #将数据流复制给所有channel a.sources.r.selector.type = replicating # 配置Source组件 a.sources.r.type = exec #exec表示数据源来自运行给定的Unix命令后生成的数据 a.sources.r.command = cat /home/bit/ys/hngyzd.csv # kafka a.sinks.k1.type = org.apache.flume.sink.kafka.KafkaSink a.sinks.k1.kafka.topic = data a.sinks.k1.kafka.bootstrap.servers = localhost:9092 a.sinks.k1.kafka.flumeBatchSize = 20 a.sinks.k1.kafka.producer.acks = 1 a.sinks.k1.kafka.producer.linger.ms = 1 a.sinks.k1.kafka.producer.compression.type = snappy a.channels.c1.type = memory a.channels.c1.capacity = 100000 a.channels.c1.transactionCapacity = 100 # mysql a.sinks.k2.type =com.us.flume.MysqlSink a.sinks.k2.hostname=localhost a.sinks.k2.port=3306 a.sinks.k2.databaseName=ys a.sinks.k2.tableName=table1 a.sinks.k2.user=bit a.sinks.k2.password=123456 a.channels.c2.type = memory a.channels.c2.capacity = 100000 a.channels.c2.transactionCapactiy = 2000 # hdfs a.sinks.k3.type = hdfs a.sinks.k3.hdfs.path = hdfs://localhost:9000/user/bit/ys #积攒多少个Event才flush到HDFS一次 a.sinks.k3.hdfs.batchSize = 100 #设置文件类型，可支持压缩 a.sinks.k3.hdfs.fileType = DataStream #多久生成一个新的文件 a.sinks.k3.hdfs.rollInterval = 5 a.channels.c3.type = memory a.channels.c3.capacity =100000 a.channels.c3.transactionCapacity = 100 # Bind the source and sink to the channel a.sources.r.channels = c1 c2 c3 a.sinks.k1.channel = c1 a.sinks.k2.channel = c2 a.sinks.k3.channel = c3

- HDFS 目的地：a.sinks.k3.type = hdfs 表示将数据写入 HDFS，a.sinks.k3.hdfs.path = hdfs://localhost:9000/user/bit/ys 表示将数据写入到本地的 HDFS 文件系统中的 /user/bit/ys 目录下。a.sinks.k3.hdfs.batch...

优化这段代码：降低这段代码重复率:def crossSol(model): sol_list=copy.deepcopy(model.sol_list) model.sol_list=[] while True: f1_index = random.randint(0, len(sol_list) - 1) f2_index = random.randint(0, len(sol_list) - 1) if f1_index!=f2_index: f1 = copy.deepcopy(sol_list[f1_index]) f2 = copy.deepcopy(sol_list[f2_index]) if random.random() <= model.pc: cro1_index=int(random.randint(0,len(model.demand_id_list)-1)) cro2_index=int(random.randint(cro1_index,len(model.demand_id_list)-1)) new_c1_f = [] new_c1_m=f1.node_id_list[cro1_index:cro2_index+1] new_c1_b = [] new_c2_f = [] new_c2_m=f2.node_id_list[cro1_index:cro2_index+1] new_c2_b = [] for index in range(len(model.demand_id_list)): if len(new_c1_f)<cro1_index: if f2.node_id_list[index] not in new_c1_m: new_c1_f.append(f2.node_id_list[index]) else: if f2.node_id_list[index] not in new_c1_m: new_c1_b.append(f2.node_id_list[index]) for index in range(len(model.demand_id_list)): if len(new_c2_f)<cro1_index: if f1.node_id_list[index] not in new_c2_m: new_c2_f.append(f1.node_id_list[index]) else: if f1.node_id_list[index] not in new_c2_m: new_c2_b.append(f1.node_id_list[index]) new_c1=copy.deepcopy(new_c1_f) new_c1.extend(new_c1_m) new_c1.extend(new_c1_b) f1.nodes_seq=new_c1 new_c2=copy.deepcopy(new_c2_f) new_c2.extend(new_c2_m) new_c2.extend(new_c2_b) f2.nodes_seq=new_c2 model.sol_list.append(copy.deepcopy(f1)) model.sol_list.append(copy.deepcopy(f2)) else: model.sol_list.append(copy.deepcopy(f1)) model.sol_list.append(copy.deepcopy(f2)) if len(model.sol_list)>model.popsize: break

new_c2_f, new_c2_m, new_c2_b = [], f2.node_id_list[cro1_index:cro2_index+1], [] for index in range(len(model.demand_id_list)): if len(new_c1_f) if f2.node_id_list[index] not in new_c1_m: new_...

解释每个语句的输出结果，并解释为什么最后一个输出语句失败。 class Class1{ int a,b; } class Class2{ float c,d; } class Class3{ String st; Class1 c1; Class2 c2; } public class PackTest { public static void main(String[] args) { Class1 c1= new Class1(); Class2 c2= new Class2(); Class3 c3= new Class3(); System.out.println(c1.a+" "+c1.b); System.out.println(c2.c+" "+c2.d); System.out.println(c3.st); System.out.println(c3.c1); System.out.println(c3.c2); System.out.println(c3.c2.c);//为什么错误 } }

2. 第二个输出语句输出 0.0 0.0 是因为类 Class2 的两个成员变量 c 和 d 没有被初始化，默认值为 0.0。 3. 第三个输出语句输出 null 是因为类 Class3 的成员变量 st 没有被初始化，默认值为 null。 4. 第四个、第五...

试定义一个计数器类CCount,声明如下： class CCount{ int iMax; //计数最大值 int iCount; //计数器值 public: CCount(); //构造函数，对象初始化，计数值=0，iMax=100 CCount(int i, int m); //构造函数，对象初始化，计数值=i，iMax=m CCount(CCount& t); //拷贝构造函数 int Inc(); //计数器+1，并返回当前计数,当计数值超过iMax。iCount=1 int GetCount(); //返回当前计数 void Clear(); //清计数为0 }; 在如下主函数中对该类进行测试。 int main() { CCount c1, c2(0,50), c3(c2); int x; cin >> x; for (int i = 0; i < x; i++) { c1.Inc(); c2.Inc(); c3.Inc(); } c2.Clear(); cout << c1.GetCount() << c2.Inc() << c3.GetCount() << endl; return 0; } 输入输出示意如下： 200 100150 请在答题窗口录入编写的完整程序。

``` #include using namespace std; class CCount{ int iMax; //计数最大值 int iCount; //计数器值 ... //构造函数，对象初始化，计数值=... cout << c1.GetCount() << c2.Inc() << c3.GetCount() ; return 0; } ```

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WinCE.net嵌入式操作系统详解：结构、开发与特点

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vb.net 对集合中对控件名进行排序的多种方法

检查 SELECT s.* FROM student s, student s2 LEFT JOIN sc c ON s.sid = c.sid LEFT JOIN sc c2 ON s2.sid = c2.sid WHERE s.sid = 1 GROUP BY s.id HAVING COUNT(c.cid) = COUNT(c2.cid);

Select s* from student s student s2 left join sc c sc c2 on s.sid=1 and s.sid = c.sid and s2.sid =c2.sid group by s.id having count(c.cid)=count(c2.cid);

System.out.println(c3.c2.c);

使用jxgl数据库，查询既选修了“操作系统”又选修了“数据结构”的学生的学号和姓名。

谈谈体系结构描述语言Aesop、MetaH、C2、Rapide、SADL、Unicon、Wright的特点

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