C语言程序设计现代方法（第2版）-课后习题答案.pdf_c语言程序设计现代方法课后题答案,c语言程序设计现代方法答案 - CSDN文库

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printf("Size of long: %d\n", (int) sizeof(long));

printf("Size of float: %d\n", (int) sizeof(float));

printf("Size of double: %d\n", (int) sizeof(double));

printf("Size of long double: %d\n", (int) sizeof(long double));

return 0;

}

Since the type of a sizeof expression may vary from one implementation

to another, it's necessary in C89 to cast sizeof expressions to a known

type before printing them. The sizes of the basic types are small numbers,

so it's safe to cast them to int. (In general, however, it's best to cast

sizeof expressions to unsigned long and print them using %lu.) In C99,

we can avoid the cast by using the %zu conversion specification.

Chapter 8

Answers to Selected Exercises

1. [was #4] The problem with sizeof(a) / sizeof(

t

) is that it can't easily

be checked for correctness by someone reading the program. (The reader

would have to locate the declaration of a and make sure that its elements

have type

t

.)

2. [was #8] To use a digit d (in character form) as a subscript into the

array a, we would write a[d-'0']. This assumes that digits have

consecutive codes in the underlying character set, which is true of ASCII

and other popular character sets.

7. [was #10]

const int segments[10][7] = {{1, 1, 1, 1, 1, 1},

{0, 1, 1},

{1, 1, 0, 1, 1, 0, 1},

{1, 1, 1, 1, 0, 0, 1},

{0, 1, 1, 0, 0, 1, 1},

{1, 0, 1, 1, 0, 1, 1},

{1, 0, 1, 1, 1, 1, 1},

{1, 1, 1},

{1, 1, 1, 1, 1, 1, 1},

{1, 1, 1, 1, 0, 1, 1}};

Answers to Selected Programming Projects

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行走的瓶子Yolo

2023-07-28

课后习题答案的解释与实际编程相符合，很实用，能帮助读者更好地掌握C语言程序设计的应用。

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