HEVC标准中的Tile特性详解

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"本文是IEEE期刊中的一篇文章,深入探讨了HEVC(高效率视频编码)标准中的Tile特性,以及相关的实验数据和对比分析。文章由Kiran Misra等人撰写,详细介绍了Tiles如何增强并行处理的效率,改进最大传输单元(MTU)匹配,减少线性缓冲区内存,并实现兴趣区域编码等功能。" 在HEVC(H.265)标准中,Tile是一个重要的新特性,它将图片分割成独立的矩形区域,这一划分带来了诸多优势。首先,Tiles提高了新标准的“并行友好性”,相比于以前基于切片的方法,能更有效地利用并行架构提高编码效率。这使得在多核处理器上进行视频编码时,各个Tile可以独立处理,显著提升了处理速度。 其次,Tiles有助于优化最大传输单元(MTU)的匹配。在视频流传输中,MTU大小的适应性对网络传输效率至关重要,而Tiles结构使得MTU大小可以根据Tile的边界灵活调整,减少了因不匹配导致的分包和重组开销。 再者,Tiles特性还减少了线性缓冲区的内存需求。每个Tile编码时只需存储其自身的缓冲数据,降低了系统内存的总体需求,尤其对于内存有限的设备,这是一个显著的优点。 此外,文章中还提出了一种基于Tile的兴趣区域编码方法。这种方法允许对视频中的特定区域(如人物、重要事件等)进行优先编码,以提高这部分区域的质量,满足特定应用场景的需求,例如监控、体育赛事直播等。 文章通过实验数据展示了不同并行化因子和MTU大小要求下的编码效率,并分析了Tile-based ROI编码方法的效果。这些实验结果为理解Tiles在实际应用中的性能提供了有价值的参考。 关键词:视频编码,多核处理,高效率视频编码,Tiles。 这篇IEEE文章详细阐述了HEVC标准中Tiles的引入、工作原理及其带来的效益,包括并行处理能力的提升、MTU匹配的优化、内存使用效率的增加,以及兴趣区域编码的实现,对于理解和利用HEVC标准进行高效视频编码具有重要意义。

Write a program to 1.Setup a simulating backing store in memory. Read the data from pdata.bin to this backing store. 2.Initialize a page table for process p, set the frame number to be -1 for each page, indicating that the page is not loaded into memory yet. 3.Read logical addresses one by one from la.txt. 4.For each logical address, a)if its page has been loaded into physical memory, simply find the frame number in the page table, then generate physical address, find and print out the physical address and data inside this address. b)if the page is used for the first time, i.e., in page table, its frame number is -1,then the page that contains this address should be loaded into a free frame in physical memory (RAM). Then update the page table by adding the frame number to the right index in the page table. Then repeat 4a). Assumption: 1.Assume the file la.txt includes the sequence of generated addresses from CPU. 2.Use a part of memory as backing store that store data for a process. 3.The backing store size is 128 bytes 4.The size of process p is 128 bytes. 5.The contents of p is included in a file pdata.bin which is a binary file. 6.Use a part of memory as RAM. The size of physical memory is 256 bytes, from 0 to 255. All the physical memory is available, allocating starting from beginning in sequence. That is, allocate frame 0 first, then frame 1, then frame 2…. 7.The size of a frame is 32 bytes, i.e., 5 bits for the offset in a frame, total number of frames is 8. At beginning, no page table is available for process p.

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