C语言用栈实现十进制转换为二进制的方法示例语言用栈实现十进制转换为二进制的方法示例
本文实例讲述了C语言用栈实现十进制转换为二进制的方法。分享给大家供大家参考，具体如下：
#include<stdio.h>
#include<malloc.h>
#include<math.h>
#include<string.h>
#include "process.h"
#define SIZE 100
#define STACKINCREMENT 10
#define OK 1
#define ERROR 0
#define TRUE 1
#define FALSE 0
typedef int Status;
typedef struct
{
int a;
} SElemType;
typedef struct
{
SElemType *base;
SElemType *top;
int stacksize;
} SqStack;
SqStack S; //定义全局变量
Status InitStack(SqStack *S)
{
S->base=(SElemType *)malloc(SIZE*sizeof(SElemType));
if(!S->base) exit(OVERFLOW);
S->top=S->base;
S->stacksize=SIZE;
return OK;
}
Status Push(SqStack *S,SElemType e)
{
if(S->top-S->base>=S->stacksize)
{
S->base=(SElemType *)malloc((S->stacksize+STACKINCREMENT)*sizeof(SElemType));
if(!S->base) exit(OVERFLOW);
S->top=S->base+S->stacksize;
S->stacksize+=STACKINCREMENT;
}
*S->top++=e;
//printf("%dwww",*--S->top);
return OK;
}
Status Stackempty(SqStack *S)
{
if(S->top==S->base)
return TRUE;
else
return FALSE;
}
Status Pop(SqStack *S,SElemType *e)
{
if(S->top==S->base) return ERROR;
*e=*--S->top;
return OK;
}
Status DtoBTrans(int N,SqStack *S)
{
SElemType e;
while(N)
{
e.a=N%2;
Push(S,e);
N=N/2;
}
while(!Stackempty(S))
{
Pop(S,&e);
printf("%d",e);
}
return OK;
}
void main()
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