E.Y. Yuan / Nuclear Physics B 891 (2015) 296–311 299
as the leading terms at order α
−3
in its Laurent expansion (2) around α
= 0. There are alto-
gether four spurious poles at s
1,2
− s
1:3
= 0, s
3:5
− s
4,5
= 0, s
1:3
− s
5,6
= 0 and s
1,2
− s
5,6
= 0
respectively, but they cancel away in the summation, resulting in 14 terms corresponding to the
14 planar scalar diagrams with the given ordering (123456), as expected.
It is interesting that Mellin transformation has been an essential tool in the wo
rk of Stieberger
and Taylor [15,16]. There it was motivated from the analogous structure of superstring and su-
pergravity amplitudes. After switching the disk boundary positions z
a
to n(n − 3)/2 cross-ratios
u
a,b
= (z
a
− z
b
)(z
a−1
− z
b+1
)/(z
a
− z
b+1
)(z
a−1
− z
b
) in one-to-one correspondence to the inde-
pendent kinematic invariants s
a,b
, Mellin transformation draws an exact correspondence between
the two sides. In this paper Mellin transformation is used as the tool to disentangle z variables
and to manifest the singularity structure of general disk integrals in a different space.
The paper is or
ganized as follows. In Section 2 we illustrate this method by discussing in great
detail its application to the simplest non-trivial case at five points. Following that, we generalize it
to any multiplicity and any orderings in Section 3, and we show how to apply multi-dimensional
contour deformation to e
xtract the leading terms from the result in 2 in the zero-slope limit, and
describe the general structure of these leading field-theory pieces obtained from this calculation.
Explicit example at six points is provided in Section 4. In the end we point out several possible
future explorations.
2. Five-point amplitude: illustrating the technique
In this section we perform our analysis at five points, which is the first non-trivial case. We
choose the canonical ordering I = (12 ...n) on the boundary of the disk, and fix the SL(2, R)
redundancy by setting {z
1
, z
2
, z
5
} ={∞, 0, 1}. As the first example we study Z[I |I ], where the
Parke–Taylor factor shares the same ordering as that on the boundary of the disk. In this case the
amplitude is
dz
3
dz
4
z
α
s
2,3
−1
3
z
α
s
2,4
4
(1 − z
3
)
α
s
3,5
(1 − z
4
)
α
s
4,5
−1
(z
4
− z
3
)
α
s
3,4
−1
, (8)
where the integration is carried out over the region 0 ≤ z
3
≤ z
4
≤ 1. We do a change of variables
as
z
3
= y
3
y
4
,z
4
= y
4
, (9)
so that both y
3
and y
4
are integrated over [0, 1], and the amplitude becomes
1
0
dy
3
dy
4
y
α
s
2,3
−1
3
y
α
s
1,5
−1
4
(1 − y
3
y
4
)
α
s
3,5
(1 − y
4
)
α
s
4,5
−1
(1 − y
3
)
α
s
3,4
−1
. (10)
Our purpose is to fully integrate out the moduli y
3
and y
4
, and so we need to decompose the factor
(1 − y
3
y
4
) so that different moduli get separated. This is done using Mellin transformation (6).
In order to avoid the appearance of any undesirable factor of the form (−1)
w
when applying (6),
we first choose to rewrite this factor as
(1 − y
3
y
4
) = (1 − y
3
) + y
3
(1 − y
4
), (11)
i.e., setting A
1
= 1 − y
3
and A
2
= y
3
(1 − y
4
) in (6). Then Mellin transformation yields
(1 − y
3
y
4
)
α
s
3,5
=
dw
2πi
B
−α
s
3,5
+ w, −w
(1 − y
3
)
α
s
3,5
−w
y
3
(1 − y
4
)
w
. (12)