C#多线程编程入门指南

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"《C#线程编程入门》是一篇由Andrew Birrell撰写的文章,旨在为有经验的程序员提供编写并发程序的实用技巧。文章首先概述了C#中的线程机制,它允许程序同时执行多个任务,通过共享内存进行同步。作者深入介绍了基本的线程和同步原语,并针对每个原语提供了详尽的教程,指导如何有效地利用它们。 教程部分着重于最佳实践,警告可能遇到的问题,并给出避免这些问题的建议。虽然本文主要以C#作为编程语言,但许多教学内容同样适用于其他支持多线程的语言,如Java。文章涉及的主题包括编程技术的并发编程(D.1.3),编程语言特性中的并发编程结构(D.3.3),以及操作系统管理中的进程管理(D.4.1)。 学习者将从中了解到设计并优化多线程程序的关键要素,如线程创建、互斥锁(Mutex)、信号量(Semaphore)、事件(Event)和任务(Task)的使用,以及如何处理线程安全问题、死锁和资源争用等。性能优化也是探讨的重要方面,包括如何根据应用场景选择合适的同步机制,以及如何避免由于并发带来的性能瓶颈。 《C#线程编程入门》是一份实用指南,适合希望在并发编程领域深化理解的开发者,无论是在C#还是其他类似环境中,都能从中获益匪浅。通过阅读这篇文章,读者不仅能掌握C#语言中的线程工具,还能提升编写高效、可维护的并发代码的能力。"
2023-07-14 上传

The Sleeping Teaching Assistant A university computer science department has a teaching assistant (TA) who helps undergraduate students with their programming assignments during regular office hours. The TA’s office is rather small and has room for only one desk with a chair and computer. There are three chairs in the hallway outside the office where students can sit and wait if the TA is currently helping another student. When there are no students who need help during office hours, the TA sits at the desk and takes a nap. If a student arrives during office hours and finds the TA sleeping, the student must awaken the TA to ask for help. If a student arrives and finds the TA currently helping another student, the student sits on one of the chairs in the hallway and waits. If no chairs are available, the student will come back at a later time. Using POSIX threads, mutex locks, and/or semaphores, implement a solution that coordinates the activities of the TA and the students. Details for this assignment are provided below. Using Pthreads, begin by creating N students. Each will run as a separate thread. The TA will run as a separate thread as well. Student threads will alternate between programming for a period of time and seeking help from the TA. If the TA is available, they will obtain help. Otherwise, they will either sit in a chair in the hallway or, if no chairs are available, will resume programming and will seek help at a later time. If a student arrives and notices that the TA is sleeping, the student must notify the TA using a semaphore. When the TA finishes helping a student, the TA must check to see if there are students waiting for help in the hallway. If so, the TA must help each of these students in turn. If no students are present, the TA may return to napping. Perhaps the best option for simulating students programming—as well as the TA providing help to a student—is to have the appropriate threads sleep for a random period of time using the sleep() API:

2023-06-04 上传