def repeat_sign(): for i in range(7): self.sign_user_list.append({"avatar": "", "name": "", "userinfo": "", "signed": "", "time": "", "date": ""}) self.avatar_list_func() self.save_sign_pos_info() # 在需要的位置调用该函数 self.timer = QtCore.QTimer() self.timer.timeout.connect(self.face_start) self.avatar_timer_sign = QtCore.QTimer() self.avatar_timer_sign.timeout.connect(self.avatar_timer_func) self.pos_start_m = 0 self.avatar_timer_sign_list = QtCore.QTimer() self.avatar_timer_sign_list.timeout.connect(self.sign_list_mover_func) self.refresh_faceconfig_timer = QtCore.QTimer() self.refresh_faceconfig_timer.timeout.connect(self.refresh_resource) self.timer.start(20) self.avatar_timer_sign.start(2000) # 调用 repeat_sign() 函数 repeat_sign()代码什么意思
时间: 2023-06-26 15:05:17 浏览: 58
这段代码定义了一个名为 "repeat_sign()" 的函数,该函数包含以下步骤:
1. 循环7次,每次将一个字典对象添加到 "sign_user_list" 列表中;
2. 调用 "avatar_list_func()" 函数;
3. 调用 "save_sign_pos_info()" 函数;
4. 创建了一个名为 "timer" 的 QTimer 对象,并将其连接到 "face_start()" 槽函数;
5. 创建了一个名为 "avatar_timer_sign" 的 QTimer 对象,并将其连接到 "avatar_timer_func()" 槽函数;
6. 设置 "pos_start_m" 变量的初始值为0;
7. 创建了一个名为 "avatar_timer_sign_list" 的 QTimer 对象,并将其连接到 "sign_list_mover_func()" 槽函数;
8. 创建了一个名为 "refresh_faceconfig_timer" 的 QTimer 对象,并将其连接到 "refresh_resource()" 槽函数;
9. 启动 "timer" 和 "avatar_timer_sign" 定时器对象,并设置它们的定时器间隔为20ms和2000ms;
10. 最后,调用 "repeat_sign()" 函数本身,以便重复执行上述步骤。
相关问题
for i in range(7): self.sign_user_list.append({"avatar": "", "name": "", "userinfo": "", "signed": "", "time": "", "date": ""}) self.avatar_list_func() self.save_sign_pos_info() self.timer = QtCore.QTimer() self.timer.timeout.connect(self.face_start) self.avatar_timer_sign = QtCore.QTimer() self.avatar_timer_sign.timeout.connect(self.avatar_timer_func) self.pos_start_m = 0 self.avatar_timer_sign_list = QtCore.QTimer() self.avatar_timer_sign_list.timeout.connect(self.sign_list_mover_func) self.refresh_faceconfig_timer = QtCore.QTimer() self.refresh_faceconfig_timer.timeout.connect(self.refresh_resource) self.timer.start(20) self.avatar_timer_sign.start(2000)代码中能否避免重复签到
可以通过添加一个判断条件来避免重复签到,比如在签到时判断当前用户是否已经签到过,如果已经签到过则不执行签到操作,示例代码如下:
```
def sign_in(self):
current_user = self.get_current_user() # 获取当前用户
for user in self.sign_user_list:
if user["name"] == current_user["name"] and user["signed"]:
# 如果当前用户已经签到过,则不执行签到操作
return
# 执行签到操作
self.update_sign_info(current_user)
self.save_sign_pos_info()
```
在这个示例中,我们在签到函数中首先获取当前用户,然后遍历已签到用户列表,如果发现当前用户已经签到过,则直接返回,否则执行签到操作。
优化下列python代码中的递归函数:def words_divi(words, n): division_words = words / n print(division_words) if division_words <= words_max: if isinstance(division_words, int): for i in range(n): sram_list.append(str(division_words) + 'x' + str(bits_max)) else: round(division_words) if division_words in words_list: for i in range(n): sram_list.append(str(division_words) + 'x' + str(bits_max)) else: while division_words < words_max: division_words = division_words + 1 if division_words in words_list: for i in range(n): sram_list.append(str(division_words) + 'x' + str(bits_max)) else: n = n + 1 print(n) words_divi(words, n) if __name__ == "__main__": words_list = [] bits_list = [] words_list.append(list(range(32, 1025, 16)) + list(range(1056, 8193, 16))) bits_list.append(list(range(16, 145, 1))) words = 16388 bits = 148 words_max = max(words_list[0]) bits_max = max(bits_list[0]) words_min = min(words_list[0]) bits_min = min(bits_list[0]) sram_list = [] num = 2 words_divi(words, num) print(sram_list)
可以使用尾递归优化来优化该递归函数,避免栈溢出的问题。具体实现方法是将递归函数中的参数改为可变参数,并将递归调用改为参数的更新,直到满足递归终止条件。以下是优化后的代码:
def words_divi(words, n, sram_list):
division_words = words / n
print(division_words)
if division_words <= words_max:
if isinstance(division_words, int):
for i in range(n):
sram_list.append(str(division_words) + 'x' + str(bits_max))
else:
round(division_words)
if division_words in words_list:
for i in range(n):
sram_list.append(str(division_words) + 'x' + str(bits_max))
else:
while division_words < words_max:
division_words = division_words + 1
if division_words in words_list:
for i in range(n):
sram_list.append(str(division_words) + 'x' + str(bits_max))
return sram_list
else:
return words_divi(words, n+1, sram_list)
if __name__ == "__main__":
words_list = []
bits_list = []
words_list.append(list(range(32, 1025, 16)) + list(range(1056, 8193, 16)))
bits_list.append(list(range(16, 145, 1)))
words = 16388
bits = 148
words_max = max(words_list[0])
bits_max = max(bits_list[0])
words_min = min(words_list[0])
bits_min = min(bits_list[0])
sram_list = []
num = 2
sram_list = words_divi(words, num, sram_list)
print(sram_list)
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