alist = ['a','a','b','b','c','a','b','a','c'] a=input() alist.remove(a) print(alist) 为什么输入b后依旧无法删除alist中的所有b
时间: 2023-12-27 13:05:28 浏览: 29
这段代码存在两个问题:
1. 只删除了第一个匹配到的元素:`remove()`方法只会删除列表中第一个匹配到的元素,因此如果要删除所有匹配元素,需要使用循环或其他方法。
2. 输入b后无法删除所有b:因为输入的是字符串类型,而列表中元素是字符类型,因此输入的字符串'b'与列表中的字符'b'并不相等,所以无法匹配到需要删除的元素。
可以使用以下代码解决这两个问题:
```python
alist = ['a', 'a', 'b', 'b', 'c', 'a', 'b', 'a', 'c']
a = input()
alist = [x for x in alist if x != a]
print(alist)
```
这段代码使用了列表推导式来删除所有匹配到的元素。同时,使用`!=`操作符来比较输入的字符串和列表中的字符是否相等,从而可以正确匹配并删除所有需要删除的元素。
相关问题
a, b = map(int, input().split())
This line of code takes input from the user in the form of two integers separated by a space. The `input()` function takes the input from the user as a string, and the `split()` function splits this string at the space and returns a list of two strings. The `map()` function applies the `int()` function to each element of this list, converting the strings to integers. Finally, the two integers are assigned to variables `a` and `b`.
For example, if the user enters "4 5" as input, `a` will be assigned the value 4 and `b` will be assigned the value 5.
a = input().split('\n') b = input().split('\n') c = a.count(b) print(c)
This code takes two inputs from the user, splits them into lists using the newline character as the delimiter, counts the number of times the second list appears in the first list, and then prints that count.
However, there is an issue with the code. The count() method expects a single argument, which is the element to be counted. In this code, the second input is being passed as the argument to count(), but count() is expecting a string or other object to count within the first list. Therefore, this code will raise a TypeError.
To fix this, we need to change the way we are using count(). One way to do this is to iterate over the first list and count the number of times the second list appears as a sublist. Here's an updated version of the code that does this:
a = input().split('\n')
b = input().split('\n')
c = 0
for i in range(len(a) - len(b) + 1):
if a[i:i+len(b)] == b:
c += 1
print(c)
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