python连连看小游戏
时间: 2023-08-28 22:07:49 浏览: 113
python写的连连看小游戏
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好的,我可以帮你实现一个简单的Python连连看小游戏。以下是基本的实现步骤:
1. 导入所需的模块和库:
```python
import pygame
import random
```
2. 设置游戏窗口和游戏界面:
```python
pygame.init()
WIDTH = 800
HEIGHT = 600
TILE_SIZE = 50
ROWS = 12
COLUMNS = 16
MARGIN = 50
screen = pygame.display.set_mode((WIDTH, HEIGHT))
pygame.display.set_caption("Python连连看小游戏")
background = pygame.Surface(screen.get_size())
background = background.convert()
background.fill((255, 255, 255))
font = pygame.font.SysFont("arial", 20)
```
3. 加载游戏图片:
```python
images = []
for i in range(1, 9):
image = pygame.image.load(f"images/{i}.png").convert_alpha()
image = pygame.transform.scale(image, (TILE_SIZE, TILE_SIZE))
images.append(image)
```
4. 初始化游戏界面的方块:
```python
board = []
for i in range(ROWS):
row = []
for j in range(COLUMNS):
tile = {
"image": None,
"rect": pygame.Rect(j * TILE_SIZE + MARGIN, i * TILE_SIZE + MARGIN, TILE_SIZE, TILE_SIZE),
"selected": False,
"matched": False,
}
row.append(tile)
board.append(row)
```
5. 随机分配图片到方块上:
```python
def shuffle_board():
for row in board:
for tile in row:
tile["image"] = random.choice(images)
```
6. 游戏主循环:
```python
running = True
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
if event.type == pygame.MOUSEBUTTONDOWN:
mouse_pos = pygame.mouse.get_pos()
for row in board:
for tile in row:
if tile["rect"].collidepoint(mouse_pos):
if not tile["selected"]:
tile["selected"] = True
else:
tile["selected"] = False
screen.blit(background, (0, 0))
for row in board:
for tile in row:
pygame.draw.rect(screen, (0, 0, 0), tile["rect"], 1)
if tile["image"]:
screen.blit(tile["image"], tile["rect"].move(1, 1))
pygame.display.flip()
pygame.quit()
```
这就是一个简单的Python连连看小游戏的基本实现步骤。当然,你还可以添加更多功能和玩法,让游戏更加有趣。
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