python连连看游戏代码

Python 连连看游戏的代码可以分为三个主要部分：游戏界面的设计、游戏逻辑的实现和用户交互的处理。以下是一个简单的示例代码，希望对您有所帮助。

游戏界面设计部分：

import tkinter as tk
import random

# 定义游戏界面大小
GAME_WIDTH = 500
GAME_HEIGHT = 500

# 定义连连看方块大小
BLOCK_SIZE = 40

# 定义游戏方块种类数
BLOCK_KINDS = 10

class Block:
    def __init__(self, kind, x, y):
        self.kind = kind
        self.x = x
        self.y = y

class GameBoard:
    def __init__(self, master):
        # 初始化主界面
        self.master = master
        self.master.geometry('{}x{}'.format(GAME_WIDTH, GAME_HEIGHT))
        self.master.title('连连看')

        # 创建画布
        self.canvas = tk.Canvas(self.master, width=GAME_WIDTH, height=GAME_HEIGHT)
        self.canvas.pack()

        # 初始化游戏方块列表
        self.blocks = []

        # 随机生成游戏方块
        for i in range(10):
            for j in range(10):
                kind = random.randint(0, BLOCK_KINDS - 1)
                x = j * BLOCK_SIZE + BLOCK_SIZE / 2
                y = i * BLOCK_SIZE + BLOCK_SIZE / 2
                block = Block(kind, x, y)
                self.blocks.append(block)

                # 在画布上绘制游戏方块
                self.canvas.create_rectangle(x - BLOCK_SIZE / 2, y - BLOCK_SIZE / 2,
                                              x + BLOCK_SIZE / 2, y + BLOCK_SIZE / 2,
                                              fill='blue')

游戏逻辑实现部分：

class GameLogic:
    def __init__(self, game_board):
        self.game_board = game_board

    def check_path(self, block1, block2):
        # 判断两个方块是否可以消除
        if block1.kind != block2.kind:
            return False

        # 判断两个方块之间是否有可行路径
        for block in self.game_board.blocks:
            if block != block1 and block != block2 and block.kind == block1.kind:
                if self.check_connect(block1, block) and self.check_connect(block2, block):
                    return True

        return False

    def check_connect(self, block1, block2):
        # 判断两个方块之间是否有直接相连的路径
        if block1.x == block2.x and abs(block1.y - block2.y) == BLOCK_SIZE:
            return True

        if block1.y == block2.y and abs(block1.x - block2.x) == BLOCK_SIZE:
            return True

        return False

    def remove_blocks(self, block1, block2):
        # 移除两个方块并更新画布
        self.game_board.blocks.remove(block1)
        self.game_board.blocks.remove(block2)

        self.game_board.canvas.delete('all')

        for block in self.game_board.blocks:
            self.game_board.canvas.create_rectangle(block.x - BLOCK_SIZE / 2,
                                                      block.y - BLOCK_SIZE / 2,
                                                      block.x + BLOCK_SIZE / 2,
                                                      block.y + BLOCK_SIZE / 2,
                                                      fill='blue')

用户交互处理部分：

class Game:
    def __init__(self):
        self.root = tk.Tk()

        # 初始化游戏界面和逻辑
        self.game_board = GameBoard(self.root)
        self.game_logic = GameLogic(self.game_board)

        # 绑定鼠标点击事件处理函数
        self.game_board.canvas.bind('<Button-1>', self.on_click)

    def on_click(self, event):
        # 获取当前鼠标点击位置
        x = event.x
        y = event.y

        # 查找最近的游戏方块
        min_distance = float('inf')
        nearest_block = None
        for block in self.game_board.blocks:
            distance = abs(block.x - x) + abs(block.y - y)
            if distance < min_distance:
                min_distance = distance
                nearest_block = block

        # 判断是否已经选中了一个方块，如果是，则尝试消除两个方块
        if hasattr(self, 'selected_block'):
            if nearest_block == self.selected_block:
                return

            if self.game_logic.check_path(self.selected_block, nearest_block):
                self.game_logic.remove_blocks(self.selected_block, nearest_block)
            else:
                self.selected_block = nearest_block
        else:
            self.selected_block = nearest_block

    def run(self):
        self.root.mainloop()

if __name__ == '__main__':
    game = Game()
    game.run()