PnP求解位姿的C++代码
时间: 2024-05-01 21:22:26 浏览: 106
PnP(Perspective-n-Point)是一种求解相机位姿的方法,可以根据已知的3D物体点和对应的2D图像点来估计相机的位置和姿态。这里提供一个使用OpenCV库实现PnP求解位姿的C++代码示例:
```c++
#include <opencv2/opencv.hpp>
int main()
{
// 3D物体坐标点
std::vector<cv::Point3f> object_points;
object_points.push_back(cv::Point3f(0, 0, 0));
object_points.push_back(cv::Point3f(0, 1, 0));
object_points.push_back(cv::Point3f(1, 0, 0));
object_points.push_back(cv::Point3f(1, 1, 0));
// 2D图像点
std::vector<cv::Point2f> image_points;
image_points.push_back(cv::Point2f(100, 100));
image_points.push_back(cv::Point2f(150, 100));
image_points.push_back(cv::Point2f(100, 150));
image_points.push_back(cv::Point2f(150, 150));
// 相机参数
cv::Mat camera_matrix = (cv::Mat_<double>(3, 3) << 1000, 0, 320, 0, 1000, 240, 0, 0, 1);
cv::Mat dist_coeffs = cv::Mat::zeros(5, 1, cv::DataType<double>::type); // 畸变系数初始化为0
// PnP求解位姿
cv::Mat rvec, tvec;
cv::solvePnP(object_points, image_points, camera_matrix, dist_coeffs, rvec, tvec);
// 输出旋转向量和平移向量
std::cout << "rvec = " << rvec << std::endl;
std::cout << "tvec = " << tvec << std::endl;
return 0;
}
```
在代码中,我们首先定义了3D物体点和对应的2D图像点,并初始化了相机参数。然后使用OpenCV库中的`solvePnP`函数求解相机的旋转向量和平移向量。最后输出求解得到的旋转向量和平移向量。
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