c语言任意输入两个数,和一个运算符,输出运算结果operator
时间: 2024-05-20 16:19:33 浏览: 8
#include <stdio.h>
int main() {
float num1, num2, result;
char operator;
printf("请输入两个数和一个运算符,格式为:数1 运算符 数2\n");
scanf("%f %c %f", &num1, &operator, &num2);
switch (operator) {
case '+':
result = num1 + num2;
printf("%.2f %c %.2f = %.2f\n", num1, operator, num2, result);
break;
case '-':
result = num1 - num2;
printf("%.2f %c %.2f = %.2f\n", num1, operator, num2, result);
break;
case '*':
result = num1 * num2;
printf("%.2f %c %.2f = %.2f\n", num1, operator, num2, result);
break;
case '/':
if (num2 == 0) {
printf("除数不能为0\n");
} else {
result = num1 / num2;
printf("%.2f %c %.2f = %.2f\n", num1, operator, num2, result);
}
break;
default:
printf("无效的运算符\n");
break;
}
return 0;
}