用C++开发一个扫雷游戏

由于您没有给出具体的要求和限制，以下是一个简单的扫雷游戏的示例代码，仅供参考：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define ROWS 10
#define COLS 10
#define MINES 10

int board[ROWS][COLS];
int revealed[ROWS][COLS];

void init_board() {
    int i, j, count = 0;
    for (i = 0; i < ROWS; i++) {
        for (j = 0; j < COLS; j++) {
            board[i][j] = 0;
            revealed[i][j] = 0;
        }
    }
    srand(time(NULL));
    while (count < MINES) {
        i = rand() % ROWS;
        j = rand() % COLS;
        if (board[i][j] != -1) {
            board[i][j] = -1;
            count++;
        }
    }
    for (i = 0; i < ROWS; i++) {
        for (j = 0; j < COLS; j++) {
            if (board[i][j] != -1) {
                if (i > 0 && j > 0 && board[i - 1][j - 1] == -1) board[i][j]++;
                if (i > 0 && board[i - 1][j] == -1) board[i][j]++;
                if (i > 0 && j < COLS - 1 && board[i - 1][j + 1] == -1) board[i][j]++;
                if (j > 0 && board[i][j - 1] == -1) board[i][j]++;
                if (j < COLS - 1 && board[i][j + 1] == -1) board[i][j]++;
                if (i < ROWS - 1 && j > 0 && board[i + 1][j - 1] == -1) board[i][j]++;
                if (i < ROWS - 1 && board[i + 1][j] == -1) board[i][j]++;
                if (i < ROWS - 1 && j < COLS - 1 && board[i + 1][j + 1] == -1) board[i][j]++;
            }
        }
    }
}

void print_board(int show_all) {
    int i, j;
    printf("  ");
    for (j = 0; j < COLS; j++) {
        printf("%d ", j);
    }
    printf("\n");
    for (i = 0; i < ROWS; i++) {
        printf("%d ", i);
        for (j = 0; j < COLS; j++) {
            if (show_all || revealed[i][j]) {
                if (board[i][j] == -1) {
                    printf("* ");
                } else {
                    printf("%d ", board[i][j]);
                }
            } else {
                printf(". ");
            }
        }
        printf("\n");
    }
}

int check_win() {
    int i, j, count = 0;
    for (i = 0; i < ROWS; i++) {
        for (j = 0; j < COLS; j++) {
            if (board[i][j] != -1 && revealed[i][j]) {
                count++;
            }
        }
    }
    return count == ROWS * COLS - MINES;
}

int main() {
    int x, y, game_over = 0;
    init_board();
    printf("Welcome to Minesweeper!\n");
    do {
        print_board(0);
        printf("Enter coordinates (x y): ");
        scanf("%d %d", &x, &y);
        if (x < 0 || x >= ROWS || y < 0 || y >= COLS) {
            printf("Invalid coordinates!\n");
        } else if (revealed[x][y]) {
            printf("Already revealed!\n");
        } else {
            revealed[x][y] = 1;
            if (board[x][y] == -1) {
                game_over = 1;
                printf("Game over!\n");
                print_board(1);
            } else {
                if (check_win()) {
                    printf("You win!\n");
                    print_board(1);
                    break;
                }
            }
        }
    } while (!game_over);
    return 0;
}

该程序生成一个 $10 \times 10$ 的扫雷游戏板，其中包含 $10$ 个地雷。玩家通过输入坐标来逐个揭开方块，如果揭开的方块是地雷，则游戏结束；否则，揭开的方块会显示数字，表示周围 $8$ 个方块中有多少个是地雷。当所有非地雷方块都被揭开时，游戏胜利。程序运行时，会提示玩家输入坐标，并在每次揭开方块后更新游戏板的状态。当游戏结束时，会显示所有方块的状态。