求s=1!+2!+3!+…+n!
时间: 2023-09-05 20:09:56 浏览: 75
可以使用循环来计算这个和。以下是使用 Python 代码实现:
```
n = int(input("请输入 n 的值:"))
s = 0
factorial = 1
for i in range(1, n+1):
factorial *= i
s += factorial
print("s =", s)
```
运行代码后,输入 n 的值,程序会计算出 s 的值。
相关问题
c语言求s=1!+2!+3!+...n!
以下是C语言求s=1!+2!+3!+...n!的代码:
```c
#include <stdio.h>
int main()
{
int n, i, j;
long long fact = 1, sum = 0;
printf("请输入一个正整数:");
scanf("%d", &n);
for (i = 1; i <= n; i++)
{
fact = 1;
for (j = 1; j <= i; j++)
{
fact *= j;
}
sum += fact;
}
printf("1!+2!+3!+...+%d! = %lld\n", n, sum);
return 0;
}
```
运行结果:
```
请输入一个正整数:5
1!+2!+3!+...+5! = 153
```
求s=1!+2!+3!+...+n!
求s=1!+2!+3!+...+n!的方法如下:
```c
#include <stdio.h>
int main()
{
int n, i, j;
long long fact = 1, sum = 0;
printf("请输入一个正整数n:");
scanf("%d", &n);
for (i = 1; i <= n; i++)
{
fact = 1;
for (j = 1; j <= i; j++)
{
fact *= j;
}
sum += fact;
}
printf("1!+2!+3!+...+%d!=%lld\n", n, sum);
return 0;
}
```