请编制一个计算y=f(x)的程序,其中： y = x x<1 y = -1/x - 1 1<=x<10 y = 5x-11 x>=10C语言

#include <stdio.h>

int main() {
float x, y;
printf("Please enter x: ");
scanf("%f", &x);
if (x < 1) {
y = x;
} else if (x >= 1 && x < 10) {
y = -1 / x - 1;
} else {
y = 5 * x - 11;
}
printf("y = %f\n", y);
return 0;
}