target = target_name_zh[index] index2 = np.argsort(predict)[0][-2] target2 = target_name_zh[index2] index3 = np.argsort(predict)[0][-3] target3 = target_name_zh[index3] index4 = np.argsort(predict)[0][-4] target4 = target_name_zh[index4] index5 = np.argsort(predict)[0][-5] target5 = target_name_zh[index5] data, obj = [], [] for x in range(-1, -12, -1): """ 这里是生成一个用于前端图表展示的数组用于渲染那个图""" data.append({"name": target_name_zh[np.argsort(predict)[0][x]], "value": float(list(predict)[0][np.argsort(predict)[0][x]])}) return {"target": target, "predict": "%.2f" % (float(list(predict)[0][index] / sum(list(predict)[0])) * 100), "target2": target2, "predict2": "%.2f" % (float(list(predict)[0][index2] / sum(list(predict)[0])) * 100), "target3": target3, "predict3": "%.2f" % (float(list(predict)[0][index3] / sum(list(predict)[0])) * 100), "target4": target4, "predict4": "%.2f" % (float(list(predict)[0][index4] / sum(list(predict)[0])) * 100), "target5": target5, "predict5": "%.2f" % (float(list(predict)[0][index5] / sum(list(predict)[0])) * 100), "data": {"data": data, "obj": obj} } with graph.as_default(): set_session(sess) data = Model.orc_img("test.png")

js代码-给定一个整数数组 nums 和一个整数目标值 target，请你在该数组中找出和为目标值的那两个整数，并返回它们的数组下标。你可以假设每种输入只会对应一个答案。但是，数组中同一个元素在答案里不能重复出现。你可以按任意顺序返回答案。来源：力扣（LeetCode）链接：https://leetcode-cn.com/problems/two-sum 著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。

js代码-给定一个整数数组 nums 和一个整数目标值 target，请你在该数组中找出和为目标值的那两个整数，并返回它们的数组下标。你可以假设每种输入只会对应一个答案。但是，数组中同一个元素在答案里不能重复出现。你可以按任意顺序返回答案。来源：力扣（LeetCode）链接：https://leetcode-cn.com/problems/two-sum 著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。

js代码-求数组中两数之和给定一个整数数组 nums 和一个目标值 target，请你在该数组中找出和为目标值的那两个整数，并返回他们的数组下标。你可以假设每种输入只会对应一个答案。但是，数组中同一个元素不能使用两遍。示例: 给定 nums = [2, 7, 11, 15], target = 9 因为 nums[0] + nums[1] = 2 + 7 = 9 所以返回 [0, 1] 来源：力扣（LeetCode）链接：https://lee

js代码-求数组中两数之和给定一个整数数组 nums 和一个目标值 target，请你在该数组中找出和为目标值的那两个整数，并返回他们的数组下标。你可以假设每种输入只会对应一个答案。但是，数组中同一个元素不能使用两遍。示例: 给定 nums = [2, 7, 11, 15], target = 9 因为 nums[0] + nums[1] = 2 + 7 = 9 所以返回 [0, 1] 来源：力扣（LeetCode）链接：https://leetcode-cn.com/problems/two-sum 著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。

def ocr(img): global graph global sess """ 识别图片""" my_image = np.array(img) print(my_image.shape) my_image = np.array([my_image]) print(my_image) with graph.as_default(): set_session(sess) predict = Model.predict(my_image) index = predict.argmax() print("CNN预测", index) target = target_name_zh[index] index2 = np.argsort(predict)[0][-2] target2 = target_name_zh[index2] index3 = np.argsort(predict)[0][-3] target3 = target_name_zh[index3] index4 = np.argsort(predict)[0][-4] target4 = target_name_zh[index4] index5 = np.argsort(predict)[0][-5] target5 = target_name_zh[index5] data, obj = [], [] for x in range(-1, -6, -1): data.append({"name": target_name_zh[np.argsort(predict)[0][x]], "value": float(list(predict)[0][np.argsort(predict)[0][x]])}) return {"target": target, "predict": "%.2f" % (float(list(predict)[0][index] / sum(list(predict)[0])) * 100), "target2": target2, "predict2": "%.2f" % (float(list(predict)[0][index2] / sum(list(predict)[0])) * 100), "target3": target3, "predict3": "%.2f" % (float(list(predict)[0][index3] / sum(list(predict)[0])) * 100), "target4": target4, "predict4": "%.2f" % (float(list(predict)[0][index4] / sum(list(predict)[0])) * 100), "target5": target5, "predict5": "%.2f" % (float(list(predict)[0][index5] / sum(list(predict)[0])) * 100), "data": {"data": data, "obj": obj}, "funfa": funfa[index] }

这是一个使用 CNN 模型进行图像识别的函数。它使用输入的图像进行识别，并返回一个包含预测结果的字典。该函数首先将图像转换为 NumPy 数组，并使用 CNN 模型对其进行预测。然后，它从预测结果中获取前五个可能的...

import numpy as np from sklearn.datasets import load_iris from sklearn.model_selection import train_test_split import matplotlib.pyplot as plt # 加载 iris 数据 iris = load_iris() # 只选取两个特征和两个类别进行二分类 X = iris.data[(iris.target==0)|(iris.target==1), :2] y = iris.target[(iris.target==0)|(iris.target==1)] # 将标签转化为 0 和 1 y[y==0] = -1 # 将数据集分为训练集和测试集 X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.2, random_state=42) # 实现逻辑回归算法 class LogisticRegression: def init(self, lr=0.01, num_iter=100000, fit_intercept=True, verbose=False): self.lr = lr self.num_iter = num_iter self.fit_intercept = fit_intercept self.verbose = verbose def __add_intercept(self, X): intercept = np.ones((X.shape[0], 1)) return np.concatenate((intercept, X), axis=1) def sigmoid(self, z): return 1 / (1 + np.exp(-z)) def loss(self, h, y): return (-y * np.log(h) - (1 - y) * np.log(1 - h)).mean() def fit(self, X, y): if self.fit_intercept: X = self.__add_intercept(X) # 初始化参数 self.theta = np.zeros(X.shape[1]) for i in range(self.num_iter): # 计算梯度 z = np.dot(X, self.theta) h = self.sigmoid(z) gradient = np.dot(X.T, (h - y)) / y.size # 更新参数 self.theta -= self.lr * gradient # 打印损失函数 if self.verbose and i % 10000 == 0: z = np.dot(X, self.theta) h = self.sigmoid(z) loss = self.__loss(h, y) print(f"Loss: {loss} \t") def predict_prob(self, X): if self.fit_intercept: X = self.__add_intercept(X) return self.__sigmoid(np.dot(X, self.theta)) def predict(self, X, threshold=0.5): return self.predict_prob(X) >= threshold # 训练模型 model = LogisticRegressio

accuracy = np.sum(y_pred == y_test) / y_test.shape[0] print(f"Accuracy: {accuracy}") # 可视化 plt.scatter(X_test[:, 0], X_test[:, 1], c=y_pred) plt.show() 请问这段代码实现了什么功能？

plot_cv_predict.zip_cross_val_predict_plot(cv._predict-python_预测

在Python的机器学习领域，cross_val_predict函数是一个非常重要的工具，主要用于交叉验证过程中的预测。这个函数来自sklearn.model_selection模块，它允许我们在不同的数据集上执行预测，以便更好地理解模型的...

代码解释clf = DecisionTreeClassifier() clf.fit(x_train,y_train) predict_target = clf.predict(x_test) print(sum(predict_target == y_test)) #预测结果与真实结果比对 print(metrics.classification_report(y_test,predict_target)) print(metrics.confusion_matrix(y_test,predict_target)) L1 = [n[0] for n in x_test] L2 = [n[1] for n in x_test] plt.scatter(L1,L2, c=predict_target,marker='x') plt.title('DecisionTreeClassifier') plt.show()

7. 使用plt.scatter()方法将测试数据x_test的第一列和第二列绘制成散点图，并将预测结果predict_target的分类用不同的颜色标记出来。 8. 使用plt.title()方法设置图表标题为“DecisionTreeClassifier”。 9. 使用plt...

解释以下代码的意义def decode_sequence(input_seq): # 将输入编码为状态向量。 states_value = encoder_model.predict(input_seq) # 生成长度为 1 的空目标序列。 target_seq = np.zeros((1, 1, num_decoder_tokens)) # 用起始字符填充目标序列的第一个字符。 target_seq[0, 0, target_token_index['\t']] = 1. # 一批序列的采样循环 # (为了简化，这里我们假设一批大小为 1)。 stop_condition = False decoded_sentence = '' while not stop_condition: output_tokens, h, c = decoder_model.predict( [target_seq] + states_value) # 采样一个 token sampled_token_index = np.argmax(output_tokens[0, -1, :]) sampled_char = reverse_target_char_index[sampled_token_index] decoded_sentence += sampled_char # 退出条件：达到最大长度或找到停止符。 if (sampled_char == '\n' or len(decoded_sentence) > max_decoder_seq_length): stop_condition = True # 更新目标序列（长度为 1）。 target_seq = np.zeros((1, 1, num_decoder_tokens)) target_seq[0, 0, sampled_token_index] = 1. # 更新状态 states_value = [h, c] return decoded_sentence for seq_index in range(100): # 抽取一个序列（训练集的一部分）进行解码。 input_seq = encoder_input_data[seq_index: seq_index + 1] decoded_sentence = decode_sequence(input_seq) print('-') print('Input sentence:', input_texts[seq_index]) print('Decoded sentence:', decoded_sentence)

2. 然后，生成一个长度为1的空目标序列target_seq，并用起始字符填充目标序列的第一个字符。 3. 接着，进入采样循环，循环中每次将目标序列和状态向量作为输入，使用解码器模型得到输出序列和新的状态向量。 4. 在...

from sklearn.model_selection import KFold kf = KFold(n_splits=5) for k, (train_index, test_index) in enumerate(kf.split(train)): train_data,test_data,train_target,test_target = train.values[train_index],train.values[test_index],target[train_index],target[test_index] clf = SGDRegressor(max_iter=1000, tol=1e-3) clf.fit(train_data, train_target) score_train = mean_squared_error(train_target, clf.predict(train_data)) score_test = mean_squared_error(test_target, clf.predict(test_data)) print(k, " 折", "SGDRegressor train MSE: ", score_train) print(k, " 折", "SGDRegressor test MSE: ", score_test, '\n')

这段代码使用了sklearn库中的KFold进行交叉验证，并且在每一折中使用了SGDRegressor进行模型训练和评估。在循环中，首先根据当前折的训练集和测试集的索引获取对应的训练数据和测试数据。...

from sklearn.tree import DecisionTreeRegressor features = df2[['age','patient_sex','current_weight']].values target = df2['current_height'].values tree = DecisionTreeRegressor() tree.fit(features,target) residuals = target - tree.predict(features) residuals_abs = np.abs(residuals) threshold = 2.5 outliers = target[residuals_abs > threshold] print(outliers) df2.iloc[outliers] 如何对这个代码进行数据可视化

plt.scatter(target, tree.predict(features), label='Predicted') # 绘制异常值的散点图 plt.scatter(outliers, tree.predict(features)[residuals_abs > threshold], color='red', label='Outliers') plt.xlabel('...

def train_model(model, env, total_episodes): # 训练模型 for episode in range(total_episodes): state = env.reset() state = np.reshape(state, [1, 6, env.window_size + 1]) done = False while not done: action = np.argmax(model.predict(state)[0]) next_state, reward, done, _ = env.step(action) next_state = np.reshape(next_state, [1, 6, env.window_size + 1]) target = reward + np.amax(model.predict(next_state)[0]) target_f = model.predict(state) target_f[0][action] = target model.fit(state, target_f, epochs=1, verbose=0) state = next_state

- target = reward + np.amax(model.predict(next_state)[0]) 计算目标值，即当前奖励加上下一步状态的最大价值。 - target_f = model.predict(state) 获取当前状态的预测值。 - target_f[0][action] = target...

from sklearn.datasets import load_iris data,target=load_iris(return_X_y=True) print('feature_value:',data.shape) print('target:',target) from sklearn.cluster import KMeans import numpy as np for i in range(0,30): kmeans=KMeans(n_clusters=3,max_iter=30,tol=0.0001, random_state=i).fit(data) label=kmeans.labels_ #print('label:',label) center=kmeans.cluster_centers_ #print('center:',center) predict=kmeans.predict(data) print('i=',i) print('predict:',predict) accuracy=np.mean(predict==target)100 print('accuracy',accuracy) #模型预测 predict=kmeans.predict(data) print('predict:',predict) import numpy as np accurancy=np.mean(predict==target)100 print('i=',i) print('accurancy',accurancy) import matplotlib.pyplot as plt import mglearn plt.figure(figsize=(10,8)) plt.subplot(221) mglearn.discrete_scatter(data[:,0],data[:,1],target,markers='^') plt.xlabel('data') plt.ylabel('origin') plt.subplot(222) mglearn.discrete_scatter(data[:,0],data[:,1],y_predict,markers='^') mglearn.discrete_scatter(kmeans.cluster_centers_[:,0],kmeans.cluster_centers_[:,1],[0,1,2],markers='o',markeredgewidth=2) plt.xlabel('data') plt.ylabel('y_predict') plt.show()写一下注释

accuracy=np.mean(predict==target)*100 print('accuracy',accuracy) 4. 输出聚类的预测结果，并计算准确率： python predict=kmeans.predict(data) print('predict:',predict) import numpy as np ...

import pandas as pdfrom sklearn.ensemble import RandomForestClassifierfrom sklearn.metrics import accuracy_score, confusion_matrix# 读取数据data = pd.read_excel('data.xlsx')# 分割训练集和验证集train_data = data.sample(frac=0.8, random_state=1)test_data = data.drop(train_data.index)# 定义特征变量和目标变量features = ['feature1', 'feature2', 'feature3']target = 'target'# 训练随机森林模型rf = RandomForestClassifier(n_estimators=100, random_state=1)rf.fit(train_data[features], train_data[target])# 在验证集上进行预测并计算精度和混淆矩阵pred = rf.predict(test_data[features])accuracy = accuracy_score(test_data[target], pred)confusion_mat = confusion_matrix(test_data[target], pred)print('Accuracy:', accuracy)print('Confusion matrix:')print(confusion_mat)# 读取新数据文件并预测结果new_data = pd.read_excel('new_data.xlsx')new_pred = rf.predict(new_data[features])new_data['predicted_target'] = new_prednew_data.to_excel('predicted_results.xlsx', index=False)改进代码输出混淆矩阵图片

features = ['feature1', 'feature2', 'feature3'] target = 'target' # 训练随机森林模型 rf = RandomForestClassifier(n_estimators=100, random_state=1) rf.fit(train_data[features], train_data[target]) # ...

#target一共9个类别。由于是字符型，定义一个函数将target的类别标签转为index表示，方便后面计算交叉熵 def target2idx(targets): target_idx = [] target_labels = ['Class_1', 'Class_2', 'Class_3', 'Class_4', 'Class_5', 'Class_6', 'Class_7', 'Class_8', 'Class_9','Class_10'] for target in targets: target_idx.append(target_labels.index(target)) return target_idx #向量转化函数(提供参考，自行选择是否使用) def convert_to_vectors(c): m = len(c) k = np.max(c) + 1 y = np.zeros(m * k).reshape(m,k) for i in range(m): y[i][c[i]] = 1 return y #特征处理函数(提供参考，自行选择是否使用) def process_features(X): scaler = MinMaxScaler(feature_range=(0,1)) X = scaler.fit_transform(1.0*X) m, n = X.shape X = np.c_[np.ones((m, 1)), X] return X数据获取样例，可自行处理 X = np.array(data)[:,1:-1].astype(float) c = target2idx(data['target']) y = convert_to_vectors(c) #划分训练集和测试集比例在0.1-0.9之间 X_train, X_test, y_train, y_test, c_train, c_test = train_test_split(X, y, c, random_state = 0, test_size = 0.2)#模型训练及预测#计算指标，本指标使用加权的方式计算多分类问题，accuracy和recall相等，可将其原因写入报告 accuracy = accuracy_score(c_test, c_pred) precision = precision_score(c_test, c_pred,average = 'weighted') recall = recall_score(c_test, c_pred,average = 'weighted') f1 = f1_score(c_test, c_pred,average = 'weighted') print("accuracy = {}".format(accuracy)) print("precision = {}".format(precision)) print("recall = {}".format(recall)) print("f1 = {}".format(f1))补全代码

target_idx.append(target_labels.index(target)) return target_idx # 将分类问题中的目标变量转化为独热编码向量 def convert_to_vectors(c): m = len(c) k = np.max(c) + 1 y = np.zeros(m * k)....

iris = load_iris() iris_data = pd.DataFrame(data= np.c_[iris['data'], iris['target']], columns= iris['feature_names'] + ['target']) iris_data['target'] = iris_data['target'].astype(int) iris_data['target'] = iris_data['target'].astype('category') iris_data_train = iris_data.sample(frac=0.7, random_state=1) iris_data_test = iris_data.drop(iris_data_train.index) model = BayesianModel([('sepal length (cm)', 'target'), ('sepal width (cm)', 'target'), ('petal length (cm)', 'target'), ('petal width (cm)', 'target')]) model.fit(iris_data_train, estimator=MaximumLikelihoodEstimator) inference = VariableElimination(model) predict_data = [] for index, row in iris_data_test.iterrows(): query = inference.query(variables=['target'], evidence={ 'sepal length (cm)': row['sepal length (cm)'], 'sepal width (cm)': row['sepal width (cm)'], 'petal length (cm)': row['petal length (cm)'], 'petal width (cm)': row['petal width (cm)'] }) predict_data.append(int(query.variables[0].str().split('[')[1].split(']')[0])) accuracy_score(iris_data_test['target'], predict_data)上述代码出现以下错误invalid literal for int() with base 10: 'target'

accuracy_score(iris_data_test['target'], predict_data) 你传递了一个类别（category）类型的数据用于计算预测结果的准确率，而 accuracy_score 函数需要传递整数类型的数据。你可以将 iris_data_test['...

def evaluate_model(model, test_data,vectorizer): test_vectors = [] for text in test_data['sms']: tokens = bert_tokenize(text) test_vectors.append(" ".join(tokens)) test_vectors = vectorizer.transform(test_vectors) pred_probs = model.predict_proba(test_vectors)[:, 1] fpr, tpr, thresholds = roc_curve(test_data['target'], pred_probs) auc_score = roc_auc_score(test_data['target'], pred_probs) return fpr, tpr, auc_score给这个函数加上KS值

2. 计算预测标签为1和0的概率分布 3. 计算预测标签为1和0的累计概率分布 4. 计算KS值下面是加上KS值的代码实现： from sklearn.metrics import roc_curve, roc_auc_score def evaluate_model(model, test_...

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