select b.name,b.nature,b.orgName from base_e_route_basesection b 改写SQL如果b.nature等于 还贷性路段 ，则不查询b.name，以b.orgName分组，否则以b.name分组查询

以下是改写后的 SQL 语句：

SELECT
    CASE WHEN b.nature = '还贷性路段' THEN NULL ELSE b.name END AS name,
    b.nature,
    b.orgName
FROM
    base_e_route_basesection b
GROUP BY
    CASE WHEN b.nature = '还贷性路段' THEN b.orgName ELSE b.name END,
    b.nature,
    b.orgName

如果 `b.nature` 等于 '还贷性路段'，则将 `b.name` 赋值为 `NULL`，否则保留原值。然后根据不同情况分别进行分组，以实现查询需求。

相关问题

SELECT CASE WHEN b.nature = '还贷性路段' THEN b.orgName ELSE b.NAME END AS NAME, b.nature, b.orgName, SUM(d.authBuildMoney) authBuildMoney, SUM(d.designMoney) designMoney, SUM(d.authSupervisorMoney) authSupervisorMoney FROM base_e_route_basesection b LEFT JOIN system_organization o ON b.org_id = o.organizationId LEFT JOIN mat_plan_planfreeway_detail d on d.sonOrgId = o.organizationId WHERE b.isUse = '1' AND b.orgName IS NOT NULL AND d.parentName = '路面工程' AND d.planType = '养护工程' GROUP BY CASE WHEN b.nature = '还贷性路段' THEN b.orgName ELSE b.NAME END ORDER BY b.nature DESC, o.CODE ASC 这条sql统计有误，如何修改

无法准确判断统计有误的原因，但是可以提供一些可能的修改建议：

1. 检查数据源是否正确，确保统计的数据来源正确；
2. 检查 WHERE 条件是否正确，确保过滤出的数据符合预期；
3. 检查 GROUP BY 是否正确，确保分组的维度和统计的维度一致；
4. 检查 SELECT 和 GROUP BY 是否一致，确保 SELECT 中的字段都在 GROUP BY 中出现过；
5. 检查 ORDER BY 是否正确，确保排序的字段存在且符合预期。

SELECT t1.org_id AS sonOrgId, t1.orgName AS sonOrgName, t1.id AS routeBasesectionId, t1.`name` AS routeBasesectionName, t1.nature, zw.billCode AS diseaseTypeSn, COUNT( t3.id ) AS num, ( CASE WHEN sum( CASE WHEN zw.`status` = '2' THEN zw.workNum END ) IS NOT NULL THEN sum( CASE WHEN zw.`status` = '2' THEN zw.workNum END ) WHEN sum( CASE WHEN zw.`status` = '1' THEN zw.workNum END ) IS NOT NULL THEN sum( CASE WHEN zw.`status` = '1' THEN zw.workNum END ) ELSE sum( CASE WHEN zw.`status` = '0' THEN zw.workNum END ) END ) AS totalAmount FROM mat_zx_section t3 JOIN base_bridge bb ON bb.id = t3.qshMainId LEFT JOIN mat_zx_workload zw ON zw.mainId = t3.id LEFT JOIN base_e_route_basesection t1 ON t3.baseRoute = t1.id LEFT JOIN main_construct t4 ON t3.constructId = t4.id -- 施工申请 LEFT JOIN main_construct_check t5 ON t5.id = t3.acceptanceId -- 施工申请验收 WHERE t5.process_status = '100' GROUP BY zw.billCode, t1.id, t1.nature, t1.org_id ORDER BY t1.org_id, t1.id, zw.billCode UNION ALL SELECT son_org_id AS sonOrgId, son_org_name AS sonOrgName, route_id AS routeBasesectionId, route_name AS routeBasesectionName, route_type AS nature, disease_type_sn AS diseaseTypeSn, num AS num, total_amount AS totalAmount FROM base_history_repair_statistics；这条sql语句执行失败

这个 SQL 语句可能会因为分号（;）导致执行失败。请尝试将分号（;）删除，然后再次执行该 SQL 语句。如下所示：

SELECT 	t1.org_id AS sonOrgId, 	t1.orgName AS sonOrgName, 	t1.id AS routeBasesectionId, 	t1.`name` AS routeBasesectionName, 	t1.nature, 	zw.billCode AS diseaseTypeSn, 	COUNT( t3.id ) AS num, 	( 	CASE 			 			WHEN sum( CASE WHEN zw.`status` = '2' THEN zw.workNum END ) IS NOT NULL THEN 				sum( CASE WHEN zw.`status` = '2' THEN zw.workNum END )  				WHEN sum( CASE WHEN zw.`status` = '1' THEN zw.workNum END ) IS NOT NULL THEN 					sum( CASE WHEN zw.`status` = '1' THEN zw.workNum END ) ELSE sum( CASE WHEN zw.`status` = '0' THEN zw.workNum END )  				END  				) AS totalAmount  			FROM 				mat_zx_section t3 				JOIN base_bridge bb ON bb.id = t3.qshMainId 				LEFT JOIN mat_zx_workload zw ON zw.mainId = t3.id 				LEFT JOIN base_e_route_basesection t1 ON t3.baseRoute = t1.id 				LEFT JOIN main_construct t4 ON t3.constructId = t4.id -- 施工申请 				LEFT JOIN main_construct_check t5 ON t5.id = t3.acceptanceId -- 施工申请验收 				 			WHERE 				t5.process_status = '100'  			GROUP BY 				zw.billCode, 				t1.id, 				t1.nature, 				t1.org_id  			ORDER BY 				t1.org_id, 				t1.id, 				zw.billCode UNION ALL 			SELECT 				son_org_id AS sonOrgId, 				son_org_name AS sonOrgName, 				route_id AS routeBasesectionId, 				route_name AS routeBasesectionName, 				route_type AS nature, 				disease_type_sn AS diseaseTypeSn, 				num AS num, 				total_amount AS totalAmount  		FROM 	base_history_repair_statistics