The largest element of the binary search tree must be in the right subtree of the root.
时间: 2024-06-04 15:07:10 浏览: 16
That is correct. In a binary search tree, all elements in the left subtree of a node are less than the node itself, and all elements in the right subtree are greater than the node itself. Therefore, the largest element must be in the right subtree of the root, as there cannot be any elements greater than the root in the left subtree.
相关问题
用C语言Write a function to print the leaf nodes of the binary tree.
好的,我明白了。以下是一个用C语言编写的函数,可以打印出二叉树的叶子节点:
```
void printLeafNodes(struct node* root)
{
if(root == NULL)
return;
if(root->left == NULL && root->right == NULL)
{
printf("%d ", root->data);
return;
}
if(root->left)
printLeafNodes(root->left);
if(root->right)
printLeafNodes(root->right);
}
```
这个函数使用递归的方法遍历二叉树,并打印出叶子节点的值。如果节点是叶子节点,则打印出节点的值,然后返回上一级。如果节点不是叶子节点,则递归处理其左右子节点。
Assume the postorder of binary tree T is RELATIONDB, the in order of T is REILTABOND,then the preorder of T will be
To determine the preorder of T, we need to first identify the root of the binary tree. In an inorder traversal of a binary tree, the nodes to the left of the root correspond to the left subtree of the root, and the nodes to the right of the root correspond to the right subtree of the root.
From the given inorder sequence REILTABOND, we can see that the root of the binary tree T is "L".
Next, we need to determine the left and right subtrees of the root. Since the postorder traversal of T is RELATIONDB, we know that the last element "B" is the root of the right subtree of "L". To find the root of the left subtree of "L", we need to look for the last element in the postorder sequence that appears before "B" in the inorder sequence.
From the inorder sequence REILTABOND, we can see that the last element before "B" is "T". Therefore, "T" is the root of the left subtree of "L".
Now we can construct the preorder traversal of T by starting at the root "L" and recursively traversing the left and right subtrees in preorder.
The preorder traversal of T is:
- Root: L
- Left subtree: T, R, E, I, L, A
- Right subtree: B, O, N, D
Therefore, the preorder of T is LTRIELABOND.
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